Question

在这个程序中：

<BeaconView dispatch={dispatch.bind(null, store)} />

我可以拥有像

这样的东西吗？

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct person{
    char name[30];
    char address[30];
    int phoneNumber[30];
    char creditRating[30];
};

int main(){
    struct person p;
    printf("What is the person's name?\n");
    scanf(" %s", p.name);
    printf("What is the person's address?\n");
    scanf(" %s", p.address);
    printf("What is the person's phone number?\n");
    scanf("%d", &p.phoneNumber);
    printf("What is the person's credit rating?\n");
    scanf(" %s", p.creditRating);

    printf("The person's name is %s\n", p.name);
    printf("The person's address is %s\n", p.address);
    printf("The person's phone number is %d\n", p.phoneNumber);
    printf("The person's credit rating is %s\n", p.creditRating);
    return 0;
}

我想要输入100个结构。要逐一编写它们有点难：

For(i=0;i>=n;i++)
struct person [i];
printf("What is the person's name?\n");
scanf(" %s", [i].name);
printf("What is the person's address?\n");
scanf(" %s", [i].address);
printf("What is the person's phone number?\n");
scanf("%d", &[i].phoneNumber);
printf("What is the person's credit rating?\n");
scanf(" %s", [i].creditRating);

我该如何避免？

Answer 1

我希望他们的输入有100个结构，但是很难一个一个地编写它们......

只需使用所需大小的结构数组并循环遍历每个元素。像这样：

struct person p[100]; //array of structures of required size

//loop over each array element
for(int i = 0; i < 100; i++) {
    printf("What is the person's name?\n");
    scanf(" %s", p[i].name);

    printf("What is the person's address?\n");
    scanf(" %s", p[i].address);

    printf("What is the person's phone number?\n");
    scanf("%d", &p[i].phoneNumber); 
    //NOTE: you are not scanning phone number correctly.
    //try using a loop or make it a string.

    printf("What is the person's credit rating?\n");
    scanf(" %s", p[i].creditRating);
}

此外，正如其他人所建议的那样，避免使用scanf()会更好。这是why not use scanf()?的链接。但是，如果你仍然想使用scanf()，那么检查它的返回值会很好。 scanf()的返回值是读取的项目数，因为您在每个scanf() 中读取一个字符串（ phoneNumber 除外）检查scanf()是否返回1

while(scanf(" %29s", string_name) != 1) {
    printf("wrong input");
}

这里，%29s是为了避免覆盖终止空字符的空间，即字符串末尾的'\0'。在while成功扫描字符串之前，上述scanf()循环不允许程序继续。

正如@IngoLeonhardt在评论中提到的那样，如果你使用字符串来接收电话号码而不是整数数组，这需要一个循环来放置在连续索引中读取的元素，那么它会更容易。 / p>

我希望循环中有100个结构或类似的结构

1 个答案: