Question

我希望从查询联合的结果中得到一个结果...我的代码是这样的：

SELECT GROUP_CONCAT(rifDoc), idUser, user, dateDoc
FROM
(
SELECT GROUP_CONCAT(CAR.rifDoc) AS rifDoc, CAR.idUser, CAR.user, CARDETT.dateDoc
FROM car AS CAR, carDett AS CARDETT 
WHERE CAR.id>0 CAR.id=CARDETT.idDoc CARDETT.dateDoc<='2017-01-31' 
GROUP BY idUser, dateDoc

UNION ALL

SELECT GROUP_CONCAT(BK.rifDoc) AS rifDoc, BK.idUser, BK.user, GROUP_CONCAT(BK.inUso) AS inUso, GROUP_CONCAT(BK.inCarico) AS inCarico, BKDETT.dateDoc
FROM bike AS BK, bikeDett AS BKDETT 
WHERE BK.id>0 AND BK.id=BKDETT.idDoc AND BKDETT.dateDoc<='2017-01-31' 
GROUP BY idUser, dateDoc
 )

GROUP BY idUser, dateDoc

但我有这样的错误：

#1248 - Every derived table must have its own alias

有人有解决方案吗？

Answer 1

您缺少内联视图或子查询的别名，因为错误状态如

SELECT GROUP_CONCAT(rifDoc), idUser, `user`, dateDoc
FROM
(
SELECT GROUP_CONCAT(CAR.rifDoc) AS rifDoc, CAR.idUser, CAR.user, CARDETT.dateDoc
FROM car AS CAR, carDett AS CARDETT 
WHERE CAR.id>0 CAR.id=CARDETT.idDoc CARDETT.dateDoc<='2017-01-31' 
GROUP BY idUser, dateDoc

UNION ALL

SELECT GROUP_CONCAT(BK.rifDoc) AS rifDoc, BK.idUser, BK.user, GROUP_CONCAT(BK.inUso) AS inUso, GROUP_CONCAT(BK.inCarico) AS inCarico, BKDETT.dateDoc
FROM bike AS BK, bikeDett AS BKDETT 
WHERE BK.id>0 AND BK.id=BKDETT.idDoc AND BKDETT.dateDoc<='2017-01-31' 
GROUP BY idUser, dateDoc
 ) XXX     <--- here

Answer 2

每个派生表（AKA子查询）必须确实具有别名。即括号中的每个查询都必须给出一个别名（AS无论如何），可以用来在外部查询的其余部分中引用它。我不确定，但我认为你的代码应该是这样的

awk -F"|" '{count[$1]++}END{for (i in count) if (count[i] < 10){print count[i],i}}' file
3 96472

不确定代码，但解决方案是（As anythin）

UNION的MySql CONCATENATE结果

2 个答案: