我一直在尝试创建一个可以从switch调用JavaScript案例的按钮。我试图创建的脚本应该计算方形的周长和面积,但它似乎不起作用。
<html>
<body>
<form>
<input type=text id="num"><br>
<input type="button" value="area" id="abut" onclick=" return calc(this.value)">
<input type="button" value="per" id="pbut" onclick=" return calc(this.value)">
</form>
<script>
function calc(count) {
var a =parseInt(document.getElementById("num").value);
var w;
if isNaN(a) {
alert("Input a number");
}
else {
switch(count) {
case 'area' :
w=a*a;
break;
case 'per' :
w=a*4;
break;
}
document.getElementById("res").innerHTML = w;
}
}
</script>
<p id="res"></p>
</body>
</html>
答案 0 :(得分:3)
错误错误:if isNaN(a)
必须在括号之间。它应该是if (isNaN(a))
function calc(count)
{
var a = parseInt(document.getElementById("num").value);
var w;
if (isNaN(a))
{
alert("Input a number");
}
else
{
switch (count)
{
case 'area':
w = a * a;
break;
case 'per':
w = a * 4;
break;
}
document.getElementById("res").innerHTML = w;
}
}
<html>
<body>
<form>
<input type=text id="num">
<br>
<input type="button" value="area" id="abut" onclick=" return calc(this.value)">
<input type="button" value="per" id="pbut" onclick=" return calc(this.value)">
</form>
<p id="res"></p>
</body>
</html>
答案 1 :(得分:0)
您忘记在if
声明中添加括号。
if isNaN(a)
应该是
if (isNaN(a))
答案 2 :(得分:0)
<html>
<body>
<head>
<script>
function calc(count)
{
var a =parseInt(document.getElementById("num").value);
var w;
if (isNaN(a))
{
alert("Input a number");
}
else
{
switch(count)
{
case 'area' :
w=a*a;
break;
case 'per' :
w=a*4;
break;
}
document.getElementById("res").innerHTML = w;
}}
</script>
</head>
<form>
<input type=text id="num"><br>
<input type="button" value="area" id="abut" onclick=" return calc(this.value)">
<input type="button" value="per" id="pbut" onclick=" return calc(this.value)">
</form>
<p id="res"></p>
</body>
</html>