Question

我正在进行搜索，搜索工作正常，查询的唯一部分是给我的问题是什么时候比较DATE（（LiveTrip.TripDate）＆gt; = DATE（？））。

它没有给我一个错误，它只是没有带回我使用heidi sql测试此查询的任何东西，它的工作原理。日期以YYYY-MM-DD格式发布。针对比较的字段在db中具有日期数据类型。有什么建议吗？

 $Limit = $_POST['limit'];
 $Offset = $_POST['offset'];
 $TripType = $_POST['TripType'];
 $datesearch = $_POST['datesearch'];
 $Departure = "%{$_POST['Departure']}%";
 $Destination= "%{$_POST['Destination']}%";

  $stmt = $conn->prepare("SELECT
  UsersMain.Id,
  UsersMain.Name,
  UsersMain.Surname,
  LiveTrip.Id,
  LiveTrip.DepstreetAddress,
  LiveTrip.DepSubTown,
  LiveTrip.DestStreetAddress,
  LiveTrip.DestSubTown,
  LiveTrip.SeatsAvailable,
  LiveTrip.TripDate,
  LiveTrip.TripTime,
  LiveTrip.Contribution,
  LiveTrip.Comments
  FROM
  LiveTrip
INNER JOIN UsersMain ON UsersMain.Id = LiveTrip.UserId
WHERE 
LiveTrip.DepSubTown like ? 
AND
LiveTrip.DestSubTown like ? 
AND LiveTrip.TripStatus =1 AND DATE((LiveTrip.TripDate) >= DATE(?)) AND  TripType=? LIMIT ? OFFSET?");

$stmt->bind_param("ssssss",$Departure, $Destination, $TripType,$datesearch,    $Limit, $Offset);

 /* execute query */
 $stmt->execute();

 /* Store the result (to get properties) */
 $stmt->store_result();

 /* Get the number of rows */
 $num_of_rows = $stmt->num_rows;

   $stmt->bind_result($id,$Name,$Surname,$Tid,$DepstreetAddress,$DepSubTown,$DestStreetAddress,$DestSubTown,$Seats,$TripDate,$TripTime,$Contribution,$Comment);

日期字段和日期字符串php mysql之间的比较

0 个答案: