如何使用ajax将数据作为参数传递给控制器​​？

Question

我想将Array传递给Controller，但我无法提供正确的URL 当点击提交404错误

时

我的路线

Route::post('store/{data}','DataController@store');

功能

    public function store(Request $request)
{
        dd($request);

    return response()->json([
        'success' => true,

    ]);

}

Ajax

     $.ajax({
            method:'POST',
            url:"/store/"+arr,
            headers: {
                'X-CSRF-TOKEN': CSRF_TOKEN
            },
            data:arr,
            success:function(response){
            alert('successful')                }
        });

和错误

    POST http://localhost:8000/store%7Bname,number,number,address,work,$2y$10$Nl28n1pWCEaHxiHlcG.Y1On2DOdtXluHP0OvN5ih.Bvdfp/Issco2%7D 404 (Not Found)

Answer 1

根据你的路线，ajax调用应该是这样的：

   $.ajax({
            method:'POST',
            url:"/data/"+arr . . . 

或者您可以更改您的ajax工作路线：

Route::post('store/{data}','DataController@store');

Answer 2

public static void main(String[] args) throws Exception {

    Configuration configuration = new Configuration();
    configuration.setAcousticModelPath("resource:/edu/cmu/sphinx/models/en-us/en-us"); 
    configuration.setDictionaryPath("resource:/edu/cmu/sphinx/models/en-us/cmudict-en-us.dict");        
    configuration.setGrammarPath("file:src");
    configuration.setGrammarName("hello");
    configuration.setUseGrammar(true);

    LiveSpeechRecognizer recognizer = new LiveSpeechRecognizer(configuration);

    recognizer.startRecognition(true);

    SpeechResult result;
    while ((result = recognizer.getResult()) != null ) {
        System.out.format("The word is: %s\n", recognizer.getResult().getResult().toString());
    }

    recognizer.stopRecognition();
}

ajax应该是这样的：

There is no need for {data}

Answer 3

尝试 路线::得到（ '存储/ {数据}'， 'DataController类@商店'）;

并将ajax方法更改为GET

Answer 4

$ request变量始终在控制器方法中可用。添加url参数时，还应将其定义为函数参数（$ data）     

public function store(Request $request, $data)
{
    dd($data);
    return response()->json([
        'success' => true,

    ]);
}