Question

我正在研究光学标记识别问题。我找到了感兴趣区域（ROI），其中学生的卷号将被填充。哪种方法可以帮助我解码填充的圆值？我试图编码，但它没有正常运作。

图片

在此图像中给出了初始ROI。之后我应用了分割。学生填写了第三张图像，表示学生的卷号。

此图像检测381圈但实际圈圈为100

Input: Filled circle image
Output: roll number : 4216789503

image = cv2.imread("rotatedb/ROI_omr.png")
hsvimg = cv2.cvtColor(image, cv2.COLOR_BGR2HSV)
lower_blue = np.array([0,70,0])
upper_blue = np.array([255,255,255])
mask = cv2.inRange(hsvimg, lower_blue, upper_blue)
contours, hierarchy = cv2.findContours(mask.copy(), cv2.RETR_TREE, cv2.CHAIN_APPROX_NONE)
print "No. of circles",len(contours)

i=0
for contour in contours:
   (x,y),radius = cv2.minEnclosingCircle(contour)
   center = (int(x),int(y))
   radius = int(radius)
   cv2.circle(image,center,radius,(0,255,0),2)
   position = (center[0] - 10, center[1] + 10)
   text_color = (0, 0, 255)
   cv2.putText(image, str(i + 1), position, cv2.FONT_HERSHEY_SIMPLEX, 0.5, text_color, 2)
   i=i+1

cv2.imshow("thresold",image)
cv2.waitKey(0)
cv2.destroyAllWindows()

Answer 1

由于标记为黑色，因此您应该尝试对输入图像中的黑色段进行分割，并从该二进制掩模中找到轮廓并滤除圆形轮廓（您可能还需要过滤如果你愿意，可以选择有面积的轮廓）。

找到所有轮廓后，按照边界矩形的x坐标对轮廓进行排序，这将产生轮廓的顺序，因为我们在水平方向上遍历它们（cv2.findContours()返回轮廓随机顺序，因此根据您的需要对它们进行排序总是一个好主意。）

最后，您计算每个轮廓的中点并估计它们所在的圆圈。

<强>代码：

import cv2

img = cv2.imread('/Users/anmoluppal/Downloads/QYtuv.png')
MARKER_LOWER_BOUND = ( 0,  0,  0)
MARKER_UPPER_BOUND = (20, 20, 20)

img = cv2.blur(img, (7, 7))
marker_seg_mask = cv2.inRange(img, MARKER_LOWER_BOUND, MARKER_UPPER_BOUND)

# Number of rows and columns of number matrix
n_rows, n_cols = 10, 10
single_element_height, single_element_width = marker_seg_mask.shape[0]/10, marker_seg_mask.shape[1]/10

# Now find the contours in the segmented mask
img, contours, hierarchy = cv2.findContours(marker_seg_mask.copy(), cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_NONE)

# Sorting the contours w.r.t contour rect X
contours.sort(key = lambda x:cv2.boundingRect(x)[0])

# Now iterate over each contour and see if it is in circular shape
roll_number = ""
for contour in contours:
    approx = cv2.approxPolyDP(contour, 0.01*cv2.arcLength(contour,True), True)
    if len(approx) > 8:
        # Find the bounding rect of contour.
        contour_bounding_rect = cv2.boundingRect(contour)
        mid_point = contour_bounding_rect[0] + contour_bounding_rect[2]/2, contour_bounding_rect[1] + contour_bounding_rect[3]/2
        roll_num_digit = mid_point[1]/single_element_height

        # Since your numbering format is from 1, 2, 3, ... 0, So to parse the roll number correctly we need additional operation
        roll_num_digit = (roll_num_digit + 1) % 10
        roll_number += str(roll_num_digit)
print "Roll Number: ", roll_number

输出

Roll Number:  4216789503

检测OCR标记

1 个答案: