Question

我正在尝试使用这些值上的键在同一级别（进入新数组）中连接两个数组。到目前为止已经尝试过这个：

$car_all_attributes = array();
            foreach ($cars_without_price as $key => $cars) 
            {
                $keep_fare = 0;
                $i = 0;
                foreach ($data['cars_fare'] as $f_key => $fare) 
                {
                    $c_fare = (explode("-",$fare));
                    if ($c_fare[0] == $cars->chauffeur_id) 
                    {
                        $car_fare = $c_fare[1];
                        $car_all_attributes[$f_key]['old_price'] = $car_fare;
                        $car_all_attributes[$f_key][$key] = $cars;
                        $i++;
                    }
                }
            }

我得到的结果是我希望它做的很少，我得到的结果是：

）分配时我不希望这个[0]=>stdClass Object，我知道我正在做$car_all_attributes[$f_key][$key]并且添加了一个新的密钥并且所有的值都反对它，想知道是否有办法在同一级别上执行此操作结果数组看起来像这样吗？

[0] => Array
    (
                [old_price] => 460
                [chauffeur_id] => 16
                [chauffeur_avalibality] => 1
                [chauffeur_supplier_id] => 1
                [chauffeur_country_id] => 190
                [chauffeur_city_id] => 0
                [chauffeur_make] => Mercedes S 350 or similar
                [chauffeur_model] => 
                [chauffeur_car_type] => 2
                [chauffeur_transmission] => 
                [chauffeur_door] => 4
                [chauffeur_passengers] => 5
                [chauffeur_large_suitecase] => 4
                [chauffeur_small_suitecase] => 5
                [chauffeur_ac] => 1
                [chauffeur_img] => carType_145851015451.jpg
                [chauffeur_service_chaufer] => 1
                [chauffeur_service_airport] => 0
                [deleted] => 0

Answer 1

看起来您的if ($c_fare[0] == $cars->chauffeur_id) { $car_fare = $c_fare[1]; $car_all_attributes[$f_key] = (array)$cars; $car_all_attributes[$f_key]['old_price'] = $car_fare; $i++; }是一个对象。您应该取代数组或将其转换为数组。

if(isset($_POST['Send']))
{

    $name = $_POST['name'];
    $to = $_POST['to'];
    $subject = $_POST['subject'];
    $message = $_POST['message'];

    $errors = array();

    if($name == "")
    {
         $errors['error'] = "Töltsd ki a mezőt(1)!";
    }
    if($to == "")
    {
        $errors['error_mail'] = "Töltsd ki a mezőt(2)!";
    }
    // Email cim ellenőrzése
    if (!filter_var($to, FILTER_VALIDATE_EMAIL))
    {
           $errors['error_mail_valid'] = "Hibás email cím!";
    }
    if($subject == "")
    {

        $errors['error_subj'] = "Töltsd ki a mezőt(3)!";
    }
    if($message == "")
    {
        $errors['error_message'] = "Töltsd ki a mezőt(4)!";
    }
    if ($name != "" && $to != "" && $subject != "")
    {
        echo "Email elküldve";

        $name = "";
        $to = "";
        $subject = "";
        $message = "";
    }

}

Answer 2

而不是

$car_all_attributes[$f_key] = array_merge(
     array('old_price' => $car_fare), 
     (array) $cars
);

试试这个（即将对象转换为数组并将其与旧价格合并而不是添加新密钥） -

{{1}}

Answer 3

从

改变

$car_all_attributes[$f_key][$key] = $cars;

到

$car_all_attributes[$f_key] = (array)$cars;

在php codeigniter中的concatinating数组

3 个答案: