java.time

Question

我正在尝试将长值（从1970年1月1日起过去的毫秒数，即Epoch ）转换为格式为h:m:s:ms的时间。

我用作时间戳的长值，来自log4j的日志记录事件的字段timestamp。

到目前为止，我已经尝试了以下内容并且失败了：

logEvent.timeStamp/ (1000*60*60)
TimeUnit.MILLISECONDS.toMinutes(logEvent.timeStamp)

但我的价值不正确：

1289375173771 for logEvent.timeStamp
358159  for logEvent.timeStamp/ (1000*60*60) 
21489586 for TimeUnit.MILLISECONDS.toMinutes(logEvent.timeStamp)

我该怎么做？

Answer 1

试试这个：

Date date = new Date(logEvent.timeSTamp);
DateFormat formatter = new SimpleDateFormat("HH:mm:ss.SSS");
formatter.setTimeZone(TimeZone.getTimeZone("UTC"));
String dateFormatted = formatter.format(date);

有关该类接受的其他格式字符串的说明，请参阅SimpleDateFormat。

使用1200毫秒的输入查看runnable example。

Answer 2

long millis = durationInMillis % 1000;
long second = (durationInMillis / 1000) % 60;
long minute = (durationInMillis / (1000 * 60)) % 60;
long hour = (durationInMillis / (1000 * 60 * 60)) % 24;

String time = String.format("%02d:%02d:%02d.%d", hour, minute, second, millis);

Answer 3

我将向您展示三种方法（a）从长值中获取分钟字段，以及（b）使用您想要的日期格式打印它。一个使用java.util.Calendar，另一个使用Joda-Time，最后一个使用Java 8及更高版本中内置的java.time框架。

java.time框架取代了旧的捆绑日期时间类，其灵感来自Joda-Time，由JSR 310定义，并由ThreeTen-Extra项目扩展。

java.time框架是使用Java 8及更高版本时的方法。否则，如Android，请使用Joda-Time。 java.util.Date / .Calendar类非常麻烦，应该避免使用。

java.util.Date＆amp; .Calendar

final long timestamp = new Date().getTime();

// with java.util.Date/Calendar api
final Calendar cal = Calendar.getInstance();
cal.setTimeInMillis(timestamp);
// here's how to get the minutes
final int minutes = cal.get(Calendar.MINUTE);
// and here's how to get the String representation
final String timeString =
    new SimpleDateFormat("HH:mm:ss:SSS").format(cal.getTime());
System.out.println(minutes);
System.out.println(timeString);

约达时间

// with JodaTime 2.4
final DateTime dt = new DateTime(timestamp);
// here's how to get the minutes
final int minutes2 = dt.getMinuteOfHour();
// and here's how to get the String representation
final String timeString2 = dt.toString("HH:mm:ss:SSS");
System.out.println(minutes2);
System.out.println(timeString2);

<强>输出：

24
  09：24：10：254个
  24个
  09：24：10：254

java.time

long millisecondsSinceEpoch = 1289375173771L;
Instant instant = Instant.ofEpochMilli ( millisecondsSinceEpoch );
ZonedDateTime zdt = ZonedDateTime.ofInstant ( instant , ZoneOffset.UTC );

DateTimeFormatter formatter = DateTimeFormatter.ofPattern ( "HH:mm:ss:SSS" );
String output = formatter.format ( zdt );

System.out.println ( "millisecondsSinceEpoch: " + millisecondsSinceEpoch + " instant: " + instant + " output: " + output );

millisecondsSinceEpoch：1289375173771 instant：2010-11-10T07：46：13.771Z输出：07：46：13：771

Answer 4

可以使用apache commons（commons-lang3）及其DurationFormatUtils类。

<dependency>
  <groupId>org.apache.commons</groupId>
  <artifactId>commons-lang3</artifactId>
  <version>3.1</version>
</dependency>

例如：

String formattedDuration = DurationFormatUtils.formatDurationHMS(12313152);
// formattedDuration value is "3:25:13.152"
String otherFormattedDuration = DurationFormatUtils.formatDuration(12313152, DurationFormatUtils.ISO_EXTENDED_FORMAT_PATTERN);
// otherFormattedDuration value is "P0000Y0M0DT3H25M13.152S"

希望它可以帮助...

Answer 5

long second = TimeUnit.MILLISECONDS.toSeconds(millis);
long minute = TimeUnit.MILLISECONDS.toMinutes(millis);
long hour = TimeUnit.MILLISECONDS.toHours(millis);
millis -= TimeUnit.SECONDS.toMillis(second);
return String.format("%02d:%02d:%02d:%d", hour, minute, second, millis);

Answer 6

public static String timeDifference(long timeDifference1) {
long timeDifference = timeDifference1/1000;
int h = (int) (timeDifference / (3600));
int m = (int) ((timeDifference - (h * 3600)) / 60);
int s = (int) (timeDifference - (h * 3600) - m * 60);

return String.format("%02d:%02d:%02d", h,m,s);

Answer 7

否则

logEvent.timeStamp / (1000*60*60)

会给你几个小时，而不是几分钟。尝试：

logEvent.timeStamp / (1000*60)

你将得到与

相同的答案

TimeUnit.MILLISECONDS.toMinutes(logEvent.timeStamp)

Answer 8

试试这个：

    String sMillis = "10997195233";
    double dMillis = 0;

    int days = 0;
    int hours = 0;
    int minutes = 0;
    int seconds = 0;
    int millis = 0;

    String sTime;

    try {
        dMillis = Double.parseDouble(sMillis);
    } catch (Exception e) {
        System.out.println(e.getMessage());
    }


    seconds = (int)(dMillis / 1000) % 60;
    millis = (int)(dMillis % 1000);

    if (seconds > 0) {
        minutes = (int)(dMillis / 1000 / 60) % 60;
        if (minutes > 0) {
            hours = (int)(dMillis / 1000 / 60 / 60) % 24;
            if (hours > 0) {
                days = (int)(dMillis / 1000 / 60 / 60 / 24);
                if (days > 0) {
                    sTime = days + " days " + hours + " hours " + minutes + " min " + seconds + " sec " + millis + " millisec";
                } else {
                    sTime = hours + " hours " + minutes + " min " + seconds + " sec " + millis + " millisec";
                }
            } else {
                sTime = minutes + " min " + seconds + " sec " + millis + " millisec";
            }
        } else {
            sTime = seconds + " sec " + millis + " millisec";
        }
    } else {
        sTime = dMillis + " millisec";
    }

    System.out.println("time: " + sTime);

Answer 9

    long hours = TimeUnit.MILLISECONDS.toHours(timeInMilliseconds);
    long minutes = TimeUnit.MILLISECONDS.toMinutes(timeInMilliseconds - TimeUnit.HOURS.toMillis(hours));
    long seconds = TimeUnit.MILLISECONDS
            .toSeconds(timeInMilliseconds - TimeUnit.HOURS.toMillis(hours) - TimeUnit.MINUTES.toMillis(minutes));
    long milliseconds = timeInMilliseconds - TimeUnit.HOURS.toMillis(hours)
            - TimeUnit.MINUTES.toMillis(minutes) - TimeUnit.SECONDS.toMillis(seconds);
    return String.format("%02d:%02d:%02d:%d", hours, minutes, seconds, milliseconds);

将时间戳（以毫秒为单位）转换为Java中的字符串格式化时间

9 个答案:

java.util.Date＆amp; .Calendar

约达时间

java.time