Question

是否可以在Python中为Raspberry Pi提供按钮推送侦听器。我有一个非锁定按钮转到GPIO。我想在第一次按下按钮时运行一些python代码。然后我希望代码在第二个按钮上停止，无论它在第一行代码中的位置。

我使用了一个名为“flag”的切换位变量来注册按钮按钮，但显然没有监听器可以确定何时进行第二次推送。

#!/usr/bin/env python
import RPi.GPIO as GPIO
import time

Button = 16    # pin16

def setup():

    GPIO.setmode(GPIO.BOARD)          # Numbers GPIOs by physical location
    GPIO.setup(Button, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)   # Button Input

def motorcontrol():
    flag=0
    while True:
        j=GPIO.input(16)
        if j==1: #Robot is activated when button is pressed
            flag=1
            print "Robot Activated",j
        while flag==1:    
            time.sleep(5)
            print "Robot Activated for 5 seconds"
            time.sleep(5)
            print "Robot Activated for 10 seconds"
            time.sleep(5)
            print "Robot Activated for 15 seconds"

            j=GPIO.input(16)
            if j==1: #De activate robot on pushing the button
                flag=0
                print "Robot DeActivated",j
                destroy()

def destroy():
    GPIO.cleanup()                     # Release resource               

if __name__ == '__main__':     # Program start from here
    setup()
    try:
        motorcontrol()
    except KeyboardInterrupt:  # When 'Ctrl+C' is pressed, the child program destroy() will be  executed.
        destroy()

Answer 1

您无法以这种方式使用(echo "attachment name"; uuencode csvfilepath csvfilename) | mailx -s "attachment name" -r frommailID tomailids，因为您的sleep()循环无法检查您的按钮。你必须循环所有时间并检查是否是时候显示文本。

您可以使用小while来使用lees CPU。

sleep()

或者更像是大多数GUI

import time

current_time = time.time()

text_1 = current_time + 5
text_2 = current_time + 10
text_3 = current_time + 15

flag = True

while flag:

    # TODO: check your button and change `flag`

    current_time = time.time()

    if text_1 and current_time >= text_1:
        print("5 seconds")
        text_1 = None #  to stop displaying
        # or show again after 5 seconds
        #text_1 = current_time + 5

    if text_2 and current_time >= text_2:
        print("10 seconds")
        text_2 = None #  to stop displaying

    if text_3 and current_time >= text_3:
        print("15 seconds")
        text_3 = None #  to stop displaying
        flag = False

    #time.sleep(0.1)

编辑：我没有RPi所以我尝试使用自己的班级import time # --- functions --- def callback_1(): print("5 seconds") # add new task to list tasks.append( (current_time + 5, callback_1) ) def callback_2(): print("10 seconds") def callback_3(): print("15 seconds") def callback_4(): global flag flag = False # --- main --- current_time = time.time() tasks = [] tasks.append( (current_time + 5, callback_1) ) tasks.append( (current_time + 10, callback_2) ) tasks.append( (current_time + 15, callback_3) ) tasks.append( (current_time + 17, callback_4) ) flag = True while flag: # TODO: check your button current_time = time.time() # this way I execute task and remove from list new_tasks = [] for t, c in tasks: if current_time >= t: c() else: new_tasks.append( (t,c) ) tasks = new_tasks #time.sleep(0.1)来模拟它 - 但也许它可以在您的计算机上运行。它显示了您应该放置代码的位置。

GPIO

Raspberry PI Button Push Listener

1 个答案: