Question

我正在学校休息期间，我正在建立一个个人助理机器人作为挑战。它以前没有问题，但我开始得到TypeErrors，尽管我能够检查“语音”是否以字符串形式返回。我知道这是因为TypeError会在经过while循环几次之后随机弹出（所以“语音”必须不会以字符串形式返回...）

我在TypeErrors上找到了其他页面，其他内容返回None和NonTypes，如one和two，但似乎都没有帮助我解决困境。我还浏览了无数其他页面，试图寻找有用的东西，但无济于事。

错误始终显示第19行：

import speech_recognition as sr
from chatterbot import ChatBot

import Messanger_Alert as MA
import Weather
import Email_Alert
import Chat
import Run


def start():
    #bot = Chat.start()
    MA_client = MA.login()
    print "Hello Luke!"
    print "I am ready for your command! :D"
    while True:
        speech = return_audio()
        try:
            if any(word in speech for word in ("Jason", "jason")): #This is line 19
                if any(word in speech for word in ("Message", "message", "Messenger", "messenger", "Facebook", "facebook")):
                    if any(word in speech for word in ("Send", "send")):
                        MA.send_message(MA_client) 
                        print "Ready for next command!"
                    elif any(word in speech for word in ("Search Friend", "search friend", "Seach friend", "search Friend", "friend", "Friend", "friends", "Friends")):
                        MA.friend_search(MA_client)
                        print "Ready for next command!"
                    elif any(word in speech for word in ("Check", "check")):
                        MA.check_message(MA_client)
                        print "Ready for next command!"
                elif any(word in speech for word in ("Email", "email")):
                    if any(word in speech for word in ("Personal", "personal", "Home", "home")):
                        Email_Alert.login1()
                        print "Ready for next command!"
                    elif any(word in speech for word in ("School", "school", "Dorm", "dorm", "UCSD", "ucsd")):
                        Email_Alert.login2()
                        print "Ready for next command!"
                elif any(word in speech for word in ("Weather", "weather", "Forecast", "forecast")):
                    Weather.decide()
                """else:
                    Chat.talk(bot)
            else:
                Chat.talk(bot)
                """
        except sr.UnknownValueError:
            print "Error! Could not process that audio."
        except sr.RequestError as e:
            print "Error! No internet connection to Google Sound Recognizer."


def return_audio():
    r = sr.Recognizer()
    with sr.Microphone() as source:
        audio = r.listen(source)
    try:
        speech = r.recognize_google(audio)
        try:
            speech = str(speech)
            print speech
            return speech
        except TypeError:
            print "Error! Could not convert speech to string!"
    except sr.UnknownValueError:
        print "Error! Could not process that audio."
    except sr.RequestError as e:
        print "Error! No internet connection to Google Sound Recognizer."

这是我得到的确切错误：

Traceback (most recent call last):
  File "C:/Users/lukec/PycharmProjects/Sysgen_AI/Run_File.py", line 25, in <module>
    startup()
  File "C:/Users/lukec/PycharmProjects/Sysgen_AI/Run_File.py", line 14, in startup
    voice()
  File "C:/Users/lukec/PycharmProjects/Sysgen_AI/Run_File.py", line 20, in voice
    Listen.start()
  File "C:\Users\lukec\PycharmProjects\Sysgen_AI\Listen.py", line 19, in start
    if any(word in speech for word in ("Jason", "jason")): 
  File "C:\Users\lukec\PycharmProjects\Sysgen_AI\Listen.py", line 19, in <genexpr>
    if any(word in speech for word in ("Jason", "jason")): 
TypeError: argument of type 'NoneType' is not iterable

我注意到当听到奇怪的声音无法区分成单词时，TypeError会更频繁出现，但我不明白为什么。我第一次注意到这个错误，当我有一个Chatbot库对话机器人在没有发出命令时接管，并且当我从我的代码中删除时错误会停止，但是这没有解决它。任何帮助修复它并向我解释原因将不胜感激。

如果您需要我的额外文件（Messanger_Alert，Weather等），我愿意提供该代码，如果它可能有所帮助。

感谢您的帮助！

Answer 1

使用if any(word in speech for word in ("Jason", "jason")):，Python正在尝试检查word是否在speech中。您从speech获得return_audio()。当return_audio()遇到任何指定的异常时，它不会执行任何显式return语句，因此会隐式返回None，而不能在搜索任何内容时进行迭代。< / p>

要解决此问题，只需在尝试查看结果之前检查该函数是否产生了真实结果。

while True:
    speech = return_audio()
    if not speech:
        continue

对于转换后的字符串

1 个答案: