Question

使用Jackson将POJO类转换为JSON。

String jsonInString = mapper.writeValueAsString(Table 1);

我是JSON，如下所示

{

    "id": #,
    "name":"name",
    "Table 2":[
        {
            "id": #,
            "name":"name",
            "Table 3":[
                {
                    "id": #,
                    "name":"name"
                }
            ],
            "Table 4":[
                {
                    "id": #,
                    "name":"name"
                }
            ]
        },
        {
            "id": #,
            "name":"name"
        }
    ]
}

但我希望JSON像

{

    "TableName":"Table 1"
    "id": #,
    "name":"name",
    "children":[
        {
            "TableName":"Table 2"
            "id": #,
            "name":"name",
            "children":[
                {
                    "TableName":"Table 3"
                    "id": #,
                    "name":"name"
                },
                {
                    "TableName":"Table 4"
                    "id": #,
                    "name":"name"
                }
            ]
        },
        {
            "TableName":"Table 2"
            "id": #,
            "name":"name"
        }
    ]
}

如何编辑这样的json格式？提前谢谢..

我的POJO类结构就像

Table 1.java
@JsonProperty("children")
private Set<Table2> Table2 = new HashSet<Table2>(0);

Table 2.java
@JsonProperty("children")
private Set<Table1> Table1 = new HashSet<Table1>(0);
//@JsonProperty("children") 
private Set<Table3> Table3 = new HashSet<Table3>(0);
//@JsonProperty("children")
private Set<Table4> Table4 = new HashSet<Table4>(0);

Table 3.java
@JsonProperty("children")
private Set<Table2> Table2 = new HashSet<Table2>(0);

Table 4.java
@JsonProperty("children")
private Set<Table2> Table2 = new HashSet<Table2>(0);

在表2.java中，我想要Table3＆amp;儿童表4。但我不能将@JsonProperty（“children”）用于Table3＆amp;表4，它们之间会发生冲突。

"children":[
                {
                    "TableName":"Table 3"
                    "id": #,
                    "name":"name"
                },
                {
                    "TableName":"Table 4"
                    "id": #,
                    "name":"name"
                }
            ]

我们如何在这里创建Table 2.java POJO类？

Answer 1

创建正确的POJO可以解决您的问题。您可以创建如下所示的POJO

Class Table{
    String tableName;
    Long id;
    String name;
    List<Table> childrens;
}

如何编辑JSON格式？

1 个答案: