Question

在Express中，我尝试扫描POST请求并创建数组openingTimes。然后根据输入创建一个MongoDB文档。

以下代码段工作正常，但我如何制作循环而不是定义n天？

`module.exports.myController = function (request, response) {
    MongoDBModel.create({
        name: req.body.name,
 //I want to make a loop in here, so I dont have to define each day separately
        openingTimes: [{
            days: req.body.days1
            , opening: req.body.opening1
            , closing: req.body.closing1
            , closed: req.body.closed1
    }, {
            days: req.body.days2
            , opening: req.body.opening2
            , closing: req.body.closing2
            , closed: req.body.closed2
    }]
// catching errors
    }, function (err, location) {
        if (err) {
            sendJsonResponse(res, 400, err);
            console.log("error is " + err);
        }
        else {
            sendJsonResponse(res, 201, location);
        }
    });
};`

Answer 1

您可以预先创建数组（或使用返回数组的IIFE内联）。

<option><?php echo $row1['class']; ?></option>

或者使用ES6，您可以创造性地使用生成器功能制作IIFE。

var numDays = 7;
var openingTimes = [];
for (var i = 1; i <= numDays; i++) {
    openingTimes.push({
        days: reg.body['days' + i],
        opening: req.body['opening' + i],
        closing: req.body['closing' + i],
        closed: req.body['closed' + i]
    });
}
MongoDBModel.create({
    name: req.body.name,
    openingTimes: openingTimes
}, etc);

如何迭代请求对象中的字符串？

1 个答案: