我有这样的数据集
library(forcats)
g <- data.frame(var = as.factor(c("C", "B", "A")),
dt = as.POSIXct(c("2016-01-01 00:02:20","2016-02-01 00:03:43", "2016-03-01 10:00:00"), format = "%Y-%m-%d %H:%M:%S", tz = "UTC")
)
我试图根据dt字段来调整数据，但是我收到了一个错误：
fct_relevel(g$var, order(g$dt))
> fct_relevel(g$var, order(g$dt))
[1] C B A
Levels: A B C
Warning message:
Unknown levels in `f`: 1, 2, 3
>
如何解决这个问题？我想使用forcats包进行此操作。
答案 0 :(得分：1)
我们可以指定＆＃39; var＆＃39;的#include "stdafx.h"
#include <fstream>
#include <iostream>
#include <string>
#include <Windows.h>
using std::string;
using std::cout;
using std::cin;
using std::ifstream;
using std::ofstream;
int main()
{
string line;
ifstream example;
example.open("Name.txt");
getline(example, line);
if (line.compare("") == 0)
{
example.close();
string con;
cout << "Welcome to this program!\n";
cout << "Do you want to register? (y/n) ";
cin >> con;
con[0] = tolower(con[0]);
if (con.compare("n") != 0)
{
string name;
ofstream one;
one.open("Name.txt");
cout << "What's your name? ";
cin >> name;
one << name;
one.close();
cout << "See you later " << name << ".";
Sleep(4000);
}
}
else
{
cout << "Welcome back " << line << ".";
example.close();
Sleep(4000);
}
}
基于＆＃39; dt＆＃39;
levels
order根据例子，＆＃39; dt＆＃39;已经with(g, fct_relevel(var, levels(var)[order(dt)]))
#[1] C B A
#Levels: A B C
编辑，因此不会更改＆{39; var＆＃39; order的{{1}}。