Question

我有一个查询，我使用相当密集的WHERE IN子句来获取与玩家相关的ID列表。

SELECT p.name,
  0a.stat_value
FROM leaderheadsplayers p
LEFT JOIN leaderheadsplayersdata_alltime 0a
ON 0a.player_id    = p.player_id
AND 0a.stat_type   = 'kills'
WHERE p.player_id IN
  (SELECT player_id
  FROM
    (SELECT 0a.player_id
    FROM leaderheadsplayersdata_alltime 0a
    WHERE 0a.stat_type = 'kills'
    ORDER BY 0a.stat_value DESC LIMIT 0,
      20
    ) 1a
  )

问题在于我想通过使用FIND_IN_SET在我的最终结果中保留这些ID的顺序，而不再使用IN子句进行密集查询。像这样：

SELECT p.name,
  0a.stat_value
FROM leaderheadsplayers p
LEFT JOIN leaderheadsplayersdata_alltime 0a
ON 0a.player_id    = p.player_id
AND 0a.stat_type   = 'kills'
WHERE p.player_id IN
  (SELECT player_id
  FROM
    (SELECT 0a.player_id
    FROM leaderheadsplayersdata_alltime 0a
    WHERE 0a.stat_type = 'kills'
    ORDER BY 0a.stat_value DESC LIMIT 0,
      20
    ) 1a
  )
ORDER BY FIND_IN_SET(p.player_id, result_from_in_clause)

这是我目前的输出：

player_id | stat_value
3 | 304
5 | 507
4 | 208

这就是我想要的：

player_id | stat_value
5 | 507
3 | 304
4 | 208

Answer 1

简单order by应该能够做到：

SELECT p.name,
  0a.stat_value
FROM leaderheadsplayers p
LEFT JOIN leaderheadsplayersdata_alltime 0a
ON 0a.player_id    = p.player_id
AND 0a.stat_type   = 'kills'
WHERE p.player_id IN
  (SELECT player_id
  FROM
    (SELECT 0a.player_id
    FROM leaderheadsplayersdata_alltime 0a
    WHERE 0a.stat_type = 'kills'
    ORDER BY 0a.stat_value DESC LIMIT 0,
      20
    ) 1a
  )
order by 
  0a.stat_value,  p.player_id;

在FIND_IN_SET中使用MySQL IN条件

1 个答案: