Question

我有三张桌子

12-30-2016

每天有8班。每个班次都有一名医生，每班需要一些护士。护士按照医生的时间表工作。我只想计算get_shift_need_nurse(String date){}中有多少轮班没有足够的护士。我的功能是：doctor_schedule_id| room_id | date |shift | nurse_needed|nurse_have_in_room ------------------------------------------------------------------------------ 1 | 1 |12-30-2016| 1 | 3 | 2 3 | 3 |12-30-2016| 2 | 2 | 1结果应为：

12-30-2016

因为doctor_schedule_id =4班次1和班次2在每个房间都没有足够的护士。 nurse_schedule_id =4不是结果，[this, is, document, one, grumpy, two, sad, three, happy]

中有足够的护士

Answer 1

COUNT(CASE WHEN nurse_needed = nurse_have_in_room then 1 ELSE NULL END) as "HasEnoughNurses"

Answer 2

<强> SQL：

Select d.DOCTOR_SCHEDULE_ID, d.ROOM_ID, d.DT, d.SHIFT, r.ROOM_ID, r.NURSE_NEEDED, Count(*) nurse_have_in_room
  From doctor_schedule d
       Join room r on d.room_id = r.room_id
       Join nurse_schedule n On d.doctor_schedule_id = n.doctor_schedule_id
    Group by d.DOCTOR_SCHEDULE_ID, d.ROOM_ID, d.DT, d.SHIFT, r.ROOM_ID, r.NURSE_NEEDED
    Having Count(*) < r.NURSE_NEEDED

测试结果：

1   3   3   12-30-2016  2   3   2   1
2   1   1   12-30-2016  1   1   3   2

SQL - 如何获取具有条件的每个值的计数？

2 个答案: