Question

当我尝试与我的SQL数据库通信时出现以下错误。此方法从JSP页面获取两个字符串值。代码获取第一个int设置的这个星期日期。但问题是我正在尝试与数据库通信。它必须是语法错误。我尝试过使用不同的方括号

public String getSpecificSpot(String day, String hour) {

    String result = "";
    int dayNo= Integer.parseInt(day);


    Calendar cal = GregorianCalendar.getInstance();
    //System.out.println("Current week = " + Calendar.DAY_OF_WEEK);
    // Set the calendar to monday of the current week
    cal.set(Calendar.DAY_OF_WEEK, Calendar.MONDAY);
    System.out.println("Current week = " + Calendar.DAY_OF_WEEK);
    // Print dates of the current week starting on Monday
    DateFormat df = new SimpleDateFormat("yyyy-MM-dd", Locale.getDefault());
    String monday = "";
    monday = df.format(cal.getTime());
    //System.out.println(monday);

    cal.add(Calendar.DATE, dayNo);
    String currentDay = df.format(cal.getTime());
    String currentDay2= currentDay;
    System.out.println("Current DAY: "+currentDay);

    boolean found = false;
    Connection c = DBHelperClass.getConnection();
    String query = "Select * from timetableslot WHERE date BETWEEN ? 00:00:00.00' AND ? 23:59:59.999' and time= ? ";
    if (c != null) {
        try {
            PreparedStatement inserter = c.prepareStatement(query);
            inserter.setString(1, currentDay);
            inserter.setString(2, currentDay2);
            inserter.setString(3, hour);

            System.out.println("validating user: " + query);
            ResultSet resultSet = inserter.executeQuery();

            while (resultSet.next()) {

                //result = resultSet.getInt("classID");
                result= String.valueOf(resultSet.getInt("slotID"));
                System.out.println(result+" result value");
                found = true;

            }
        } catch (SQLException ex) {
            Logger.getLogger(User.class.getName()).log(Level.SEVERE, null, ex);
        }

    }
    //result="ssa";
    return result;
}

我得到的错误是：

 java.sql.SQLException: Parameter index out of range (3 > number of parameters, which is 2).

Answer 1

您好我在发布问题

之后修复了它

public String getSpecificSpot(String day, String hour) {

    String result = "";
    int dayNo= Integer.parseInt(day);


    Calendar cal = GregorianCalendar.getInstance();
    //System.out.println("Current week = " + Calendar.DAY_OF_WEEK);
    // Set the calendar to monday of the current week
    cal.set(Calendar.DAY_OF_WEEK, Calendar.MONDAY);
    System.out.println("Current week = " + Calendar.DAY_OF_WEEK);
    // Print dates of the current week starting on Monday
    DateFormat df = new SimpleDateFormat("yyyy-MM-dd", Locale.getDefault());
    String monday = "";
    monday = df.format(cal.getTime());
    //System.out.println(monday);

    cal.add(Calendar.DATE, dayNo);
    String currentDay = df.format(cal.getTime());
    String currentDay2= currentDay;
    System.out.println("Current DAY: "+currentDay);

    boolean found = false;
    Connection c = DBHelperClass.getConnection();
    String query = "Select * from timetableslot WHERE date BETWEEN ? AND ? and time= ? ";
    if (c != null) {
        try {
            PreparedStatement inserter = c.prepareStatement(query);
            inserter.setString(1, currentDay + " 00:00:00.00");
            inserter.setString(2, currentDay2+ " 23:59:59.999");
            inserter.setString(3, hour);

            System.out.println("validating user: " + query);
            ResultSet resultSet = inserter.executeQuery();

            while (resultSet.next()) {

                //result = resultSet.getInt("classID");
                result= String.valueOf(resultSet.getInt("slotID"));
                System.out.println(result+" result value");
                found = true;

            }
        } catch (SQLException ex) {
            Logger.getLogger(User.class.getName()).log(Level.SEVERE, null, ex);
        }

    }
    //result="ssa";
    return result;
}

参数索引超出范围（3>参数个数，即2）错误

1 个答案: