Question

简而言之，尝试将一个非常大的数组块分成10块，等待5秒，然后发出下一个10块。

这是我目前拥有的

Rx.Observable
   .from(hugeArray)
   .bufferCount(10) 
   .delay(5000) //want to wait 5 secs
   .flatMap(e => e) // this needs to go after to flatten the array, buffer spits out arrays of entries
   .flatMap( (data, index) => Rx.Observable.create(observer => {
       // going to render stuff here
       observer.onNext(data)
       observer.onCompleted();  

   }))
   .subscribe(val => console.log('Buffered Values:', val));

只是尝试在5秒内完成10个块，只能做一个初始延迟，然后它会发出其余的。

Answer 1

您的链条只是立即发出一切，然后安排每个块从同一时间开始等待5秒，以便在同一时刻所有块的延迟过去。

解决方案可以是使用逐个订阅每个Observable的import {RECEIVE_BABY} from '../constants' import axios from 'axios' export const receiveBaby = (baby,weight,height,sleep,diaper,feeding) =>({ type: RECEIVE_BABY, baby: baby, weight: weight, feeding: feeding, height: height, sleep: sleep, diapers: diaper }) export const getBabyById = babyId => { console.log("GET BABY BY ID") return dispatch => { Promise .all([ axios.get(`/api/baby/${babyId}`), axios.get(`/api/baby/${babyId}/weight`), axios.get(`/api/baby/${babyId}/height`), axios.get(`/api/baby/${babyId}/sleep`), axios.get(`/api/baby/${babyId}/diaper`), axios.get(`/api/baby/${babyId}/feed`) ]) .then(results => results.map(r => r.data)) .then(results => { console.log("THIS IS RESULTS in Action assadkjasdfkjl;", results) dispatch(receiveBaby(...results)); }) .catch(function(err){ console.log(err) }) }; };。

concatMap()

Rxjs：块和延迟流？

1 个答案: