Question

我想在Python中编写一个使用以下内容的正则表达式

转换所有以[alphanumeric]\n结尾的句子，并将其替换为＆＃34;。＆＃34;

所以例如

I went there
I also went there.
It is


That-
I too went there!
It went there?
It is 3

所以，让我们说

应转换为

I went there.
I also went there.
It is.


That-
I too went there!
It went there?
It is 3.

我该怎么做？

编辑：输入字符串是

s = "I went there\nI also went there.\nIt is\n\nThat-\nI too went there!\nIt went there?\nIt is 3"

此外，＆＃34;？＆＃34;不应附加＆＃34;。＆＃34;

EDIT2：我修改了示例，因此它包含一个双\n和一个以-结尾的句子。所以＆＃34; - ＆＃34;不应附加＆＃34;。＆＃34;

Answer 1

尝试这样的事情：

s = 'I went there'

if s[-1] not in ['!', ',', '.', '\n']:
    s += '.'

修改

使用您的新输入，以下内容应该有效：

new_string = ''.join('{}.\n'.format(item) if (item and item[-1] not in '!?.,-') else '{}\n'.format(item) for item in s.split('\n'))

如果您不想在\n结尾处new_string，则可以将其删除：

new_string = new_string.rstrip('\n')

<强>输出：

>>> s = "I went there\nI also went there.\nIt is\n\nThat-\nI too went there!\nIt went there?\nIt is 3" >>> new_string = ''.join('{}.\n'.format(item) if (item and item[-1] not in '!?.,-') else '{}\n'.format(item) for item in s.split('\n')) >>> >>> print(new_string) I went there. I also went there. It is. That- I too went there! It went there? It is 3.

Answer 2

使用re.sub()函数和特定正则表达式模式的简单解决方案：

s = "I went there\nI also went there.\nIt is\n\nThat-\nI too went there!\nIt went there?\nIt is 3"
s = re.sub(r'(?<=[^,.!?-\s])(\n|$)', r'.\1', s, re.M)
print(s)

输出：

I went there.
I also went there.
It is.

That-
I too went there!
It went there?
It is 3.

(\n|$) - 匹配换行符（新行）或字符串

的结尾

(?<=[^,.!?-\s]) - 确保在上述匹配

之前没有特定字符

\1 - 指的是第一个捕获组(\n|$)

在Python中添加缺少句点到换行符

2 个答案: