Question

我的任务是创建一个打开.c文件的C程序，然后用户写入一些文本，然后打印文本以及（）{} /和百分比评论的数量：整个文本C程序。到目前为止，我有这个：

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int k, j, m, n, l, z, count1 = 0, count2 = 0, count3 = 0, count4 = 0, count5 = 0, count6 = 0;
    char str[10000], chh, chhh;
    char ch, file_name[75];
    FILE *fp;

    printf("Enter the name of file you wish to see with extension .c or .txt\n");
    gets_s(file_name);

    fp = fopen_s(file_name, "r");  // reads the file

    if (fp == NULL)
    {
        perror("Error while opening the file.\n");
        _getche();
        exit(EXIT_FAILURE);
    }

    printf("The contents of %s file are :\n", file_name); //prints out the text
    int i = 0;
    while ((ch = fgetc(fp)) != EOF) {
        printf("%c", ch);
        str[i] = ch;
        i++;
    }
    int fsize = i;
    // code above opens up the symbols of the file, code below searches for specific symbols
    int count = 0;
    printf("\nEnter the character to be searched : "); //which symbol to search
    scanf_s("%c", &chh);
    for (i = 0; i < fsize; i++) {
        if (str[i] == chh)
            count++;
    }

    if (count == 0)
        printf("\nCharacter '%c' is not present", chh); //if there isn't one
    else
        printf("\nOccurence of character '%c' : %d", chh, count); //prints their number if there is

    for (k = 0; k<fsize; k++) {
        if (str[k] == '>')
            count1++;  
    }
    for (j = 0; j<fsize; j++) {
        if (str[j] == '<')
            count2++;
    }
    for (m = 0; m<fsize - 1; m++) {
        if (str[m] == '=' && str[m + 1] == '=')
            count3++;
    }
    for (n = 0; n<fsize - 4; n++) {
        if (str[n] == 'e' && str[n + 1] == 'l' && str[n + 2] == 's' && str[n + 3] == 'e') 
            count4++;
    }
    for (l = 0; l<fsize - 2; l++) {
        if (str[l] == 'i' && str[l + 1] == 'f')
            count5++;
    }

    int br;
    br = count4 + count5;
    printf("\nOccurence of character '%c' : %d", '>', count1);
    printf("\nOccurence of character '%c' : %d", '<', count2);
    printf("\nOccurence of character ==  : %d ", count3);
    printf("\nOccurence of character else : %d ", count4);
    printf("\nOccurence of character if: %d \n", count5);
    printf("\nobsht broi if+else: %d ", br);

    fclose(fp);
    return 0;
}

它打印出文件中的文本，搜索您想要的特定字符并打印出它。

PS：当我尝试在我的电脑上运行它时，Visual Studio会发出一堆错误和警告。我很困惑如何摆脱它们。 Errors image 谢谢！

Answer 1

使用GCC我可以通过改变一些方法来编译它。

将gets_s更改为gets（file_name），这会产生一个警告，指出这是一个不安全的函数。
将_getche（）更改为getchar（）
将scanf_s（）更改为scanf（）
将fopen_s（）更改为fopen（）

此代码在Linux上使用GCC编译和运行

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int k, j, m, n, l, z, count1 = 0, count2 = 0, count3 = 0, count4 = 0, count5 = 0, count6 = 0;
    char str[10000], chh, chhh;
    char ch, file_name[75];
    FILE *fp;

    printf("Enter the name of file you wish to see with extension .c or .txt\n");
    gets(file_name);

    fp = fopen(file_name, "r");  // reads the file

    if (fp == NULL)
    {
        perror("Error while opening the file.\n");
        getchar();
        exit(EXIT_FAILURE);
    }

    printf("The contents of %s file are :\n", file_name); //prints out the text
    int i = 0;
    while ((ch = fgetc(fp)) != EOF) {
        printf("%c", ch);
        str[i] = ch;
        i++;
    }
    int fsize = i;
    // code above opens up the symbols of the file, code below searches for specific symbols
    int count = 0;
    printf("\nEnter the character to be searched : "); //which symbol to search
    scanf("%c", &chh);
    for (i = 0; i < fsize; i++) {
        if (str[i] == chh)
            count++;
    }

    if (count == 0)
        printf("\nCharacter '%c' is not present", chh); //if there isn't one
    else
        printf("\nOccurence of character '%c' : %d", chh, count); //prints their number if there is

    for (k = 0; k<fsize; k++) {
        if (str[k] == '>')
            count1++;  
    }
    for (j = 0; j<fsize; j++) {
        if (str[j] == '<')
            count2++;
    }
    for (m = 0; m<fsize - 1; m++) {
        if (str[m] == '=' && str[m + 1] == '=')
            count3++;
    }
    for (n = 0; n<fsize - 4; n++) {
        if (str[n] == 'e' && str[n + 1] == 'l' && str[n + 2] == 's' && str[n + 3] == 'e') 
            count4++;
    }
    for (l = 0; l<fsize - 2; l++) {
        if (str[l] == 'i' && str[l + 1] == 'f')
            count5++;
    }

    int br;
    br = count4 + count5;
    printf("\nOccurence of character '%c' : %d", '>', count1);
    printf("\nOccurence of character '%c' : %d", '<', count2);
    printf("\nOccurence of character ==  : %d ", count3);
    printf("\nOccurence of character else : %d ", count4);
    printf("\nOccurence of character if: %d \n", count5);
    printf("\nobsht broi if+else: %d \n", br);

    fclose(fp);
    return 0;
}

Answer 2

请在下面找到我的发现。

gets_s（FILE_NAME）; - ＆GT;我不认为这是正确的。 gets_s占用2个参数而不是1请使用获取而不是尝试或简单的scanf来检查它是否正常工作。

2._getche（）请为该功能使用#include头文件。使用它可以避免这个问题。

fopen_s - ＆gt; Fopen的参数集无效。你需要一个文件指针作为第一个参数。请重新设置使用的功能。最好选择有2个参数的fopen。
scanf_s - ＆gt;有一个参数（参数），您可以在其中指定缓冲区大小。因此，您使用的上述代码sacnf_s函数是合成错误的。请相应更改。

请查找常用的已更改代码。我冒昧地将gets_s更改为gets，fopen_s更改为fopen，scanf_s更改为scanf并构建它。没有错误。请找到以下代码供您参考。

#include <stdio.h>
#include <stdlib.h>
#include<conio.h>
FILE *fp;
int main()
{
int k, j, m, n, l, z, count1 = 0, count2 = 0, count3 = 0, count4 = 0, count5 = 0, count6 = 0;
char str[10000], chh, chhh;
char ch, file_name[75];


printf("Enter the name of file you wish to see with extension .c or .txt\n");
gets(file_name);

fp = fopen(file_name, "r");  // reads the file

if (fp == NULL)
{
    perror("Error while opening the file.\n");
    getchar();
    exit(EXIT_FAILURE);
}

printf("The contents of %s file are :\n", file_name); //prints out the text
int i = 0;
while ((ch = fgetc(fp)) != EOF) {
    printf("%c", ch);
    str[i] = ch;
    i++;
}
int fsize = i;
// code above opens up the symbols of the file, code below searches for specific symbols
int count = 0;
printf("\nEnter the character to be searched : "); //which symbol to search
scanf_s("%c", &chh);
for (i = 0; i < fsize; i++) {
    if (str[i] == chh)
        count++;
}

if (count == 0)
    printf("\nCharacter '%c' is not present", chh); //if there isn't one
else
    printf("\nOccurence of character '%c' : %d", chh, count); //prints their number if there is

for (k = 0; k<fsize; k++) {
    if (str[k] == '>')
        count1++;
}
for (j = 0; j<fsize; j++) {
    if (str[j] == '<')
        count2++;
}
for (m = 0; m<fsize - 1; m++) {
    if (str[m] == '=' && str[m + 1] == '=')
        count3++;
}
for (n = 0; n<fsize - 4; n++) {
    if (str[n] == 'e' && str[n + 1] == 'l' && str[n + 2] == 's' && str[n + 3] == 'e')
        count4++;
}
for (l = 0; l<fsize - 2; l++) {
    if (str[l] == 'i' && str[l + 1] == 'f')
        count5++;
}

int br;
br = count4 + count5;
printf("\nOccurence of character '%c' : %d", '>', count1);
printf("\nOccurence of character '%c' : %d", '<', count2);
printf("\nOccurence of character ==  : %d ", count3);
printf("\nOccurence of character else : %d ", count4);
printf("\nOccurence of character if: %d \n", count5);
printf("\nobsht broi if+else: %d ", br);

fclose(fp);
return 0;

}

如果你需要任何帮助，请随时ping我:)谢谢。

写（在文件中）和打印统计

2 个答案: