Question

我需要通过公共ID合并多个json对象。我的问题是我的对象有不同的ID密钥。

var object1 = [
  { "name":"apples" ,"w": 1, "x": 2 },
  { "name":"banana" ,"w": 1, "x": 2 },
  { "name":"cherry" ,"w": 1, "x": 2 },
];
var object2 = [
  { "type":"banana" ,"y": 3, "x": 4 },
  { "type":"cherry" ,"y": 3, "x": 4 },
];

我想获得：

var object1 = [
  { "name":"apples" ,"w": 1, "x": 2 },
  { "name":"banana" ,"w": 1, "x": 4, "y": 3 },
  { "name":"cherry" ,"w": 1, "x": 4, "y": 3 },
];

我想使用相同的Array [object1]而不是创建一个新的。我创建了一个codepen here

Answer 1

循环浏览object2并使用Array.prototype.find更新水果 - 请参阅下面的演示：

＆＃13;

var object1 = [{ "name":"apples" ,"w": 1, "x": 2 },{ "name":"banana" ,"w": 1, "x": 2 },{ "name":"cherry" ,"w": 1, "x": 2 }];
var object2 = [{ "type":"banana" ,"y": 3, "x": 4 },{"type":"cherry" ,"y": 3, "x": 4 }];

object2.forEach(function(e){
  var found = object1.find(function(k){
    return k.name === e.type;
  });
  if(found) {
    found.x = e.x;
    found.y = e.y;
  }
});

console.log(object1);

＆＃13;

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＆＃13;

Answer 2

您可以使用reduce()创建新数组，并查找相同类型的object2对象中是否存在具有相同名称的对象。

var object1 = [
  { "name":"apples" ,"w": 1, "x": 2 },
  { "name":"banana" ,"w": 1, "x": 2 },
  { "name":"cherry" ,"w": 1, "x": 2 },
];
var object2 = [
  { "type":"banana" ,"y": 3, "x": 4 },
  { "type":"cherry" ,"y": 3, "x": 4 },
];


var result = object1.reduce(function(r, e) {
  var o = object2.find(a => e.name == a.type);
  r.push(o ? Object.assign({}, e, {x: o.x, y: o.y}) : e);
  return r;
}, [])

console.log(result)

Answer 3

我为你的问题找到了解决方案，你能试试吗？

＆＃13;

var object1 = [
  { "name":"apples" ,"w": 1, "x": 2 },
  { "name":"banana" ,"w": 1, "x": 2 },
  { "name":"cherry" ,"w": 1, "x": 2 },
];
var object2 = [
  { "type":"banana" ,"y": 3, "x": 4 },
  { "type":"cherry" ,"y": 3, "x": 4 },
];

function mergeObject(obj1,obj2){
    var obj3 = {};
    for (var attrname in obj1) { obj3[attrname] = obj1[attrname]; }
    for (var attrname in obj2) { obj3[attrname] = obj2[attrname]; }
    return obj3;
}

function mergeObjectInArray(firstArray,  firstArrayKey, secondaryArray, secondaryArrayKey) {
  var resultArray = new Array();
  for(var firstArrayIndex in firstArray) {
    var firstArrayObject = firstArray[firstArrayIndex];
    var resultArrayObject = firstArrayObject;
    for(var secondaryArrayIndex in secondaryArray) {
    var secondaryArrayObject = secondaryArray[secondaryArrayIndex];
      if(firstArrayObject[firstArrayKey] === secondaryArrayObject[secondaryArrayKey]) {
        resultArrayObject = mergeObject(firstArrayObject,secondaryArrayObject);
        delete resultArrayObject[secondaryArrayKey];
      }
    }
    resultArray.push(resultArrayObject);
  }
  return resultArray;
  
}

var resultArray = mergeObjectInArray(object1, "name", object2, "type");


// Assuming JSON.stringify - not available in IE<8
console.log(JSON.stringify( resultArray ) );

＆＃13;

合并具有不同ID的多个对象数组

3 个答案: