Question

如果你有格式的C＃类，那么

我在F＃中know that：

public class Person {
    public DateTime BirthDate { get; set; }
    public string Name { get; set; }
}

你可以像这样初始化它，这很好：

let p = new Person (Name = "John", BirthDate = DateTime.Now)

但是如果C＃类也有这样的构造函数，你将如何在F＃中初始化它：

public class Person {
    public Person(int id)
    {
        Id = id
    }

    public int Id {get; private set;}
    public DateTime BirthDate { get; set; }
    public string Name { get; set; }
}

我们是否被迫使用这种结构？

let p = new Person (123)
p.Name <- "John"
p.BirthDate <- DateTime.Now

Answer 1

对auto属性使用equivilent F＃语法可能如下所示。您可以按如下方式组合构造函数和属性初始化：

type Person(id : int) =
    member val Id = id with get,set
    member val BirthDate = DateTime.MinValue with get,set
    member val Name = "" with get,set

let p = Person(5, Name = "Stu")
p |> Dump

Answer 2

System.UriBuilder BCL类看起来像OP中的Person类，所以我将以此为例：

> let ub = UriBuilder("http://blog.ploeh.dk", Path = "about");;    
val ub : UriBuilder = http://blog.ploeh.dk:80/about

使用构造函数进行F＃对象初始化

2 个答案: