我所做的是从文件加载一些HTML,我试图修改该HTML中的一些元素。
初始化如下所示:
var id = player_info["ID"];
$("#main_container").append(
$("<div />").attr({class: "player_container", id: "player_" + id}).css("display", "none")
);
// Add all information to the player container
var player_container = $("#player_" + id);
player_container.load("player_layout.html");
player_layout.html
看起来像这样:
<div class="player_name">
</div>
<div class="player_chips">
Chips:
<br/>
<span class='bidding'></span>/<span class='chips'></span>
</div>
<div class="player_stats">
Wins / Losses
<br/>
<span class="wins"></span>/<span class="losses"></span>(<span class="total_games"></span>)
<br/><br/>
Chips Won / Chips Lost
<br/>
<span class="chips_won"></span>/<span class="chips_lost"></span>
</div>
<button class="player_won">Player Has Won</button>
然后我想修改一些元素,特别是类。我最初这样做的一个例子是:
player_container.find(".player_name").text(player_info['username']);
这不起作用,所以我尝试将find
与children
和text
切换为html
,但这似乎不起作用。然后我尝试了这个:
$('> .player_name', player_container).html(player_info['username']);
但这也行不通。我知道我可以使用DOM来获取childNodes
并比较类名,但是有很多类需要修改,我也想知道这是否可以在JQuery中使用。提前感谢您的帮助。
答案 0 :(得分:4)
您需要使用.load()
var player_container = $("#player_" + id);
player_container.load("player_layout.html", function(){
player_container.find(".player_name").text(player_info['username']);
});