Question

我正在尝试使用async / await模式ftpupload一个zipfile：

    private async void button2_Click(object sender, RoutedEventArgs e)
    {

        await processFtp();

    }
    async Task processFtp()
    {
        string result = "";
        string ftpHost = "ftp://mysite/mysubdir";

        string ftpUser = "itsme";

        string ftpPassword = "mypw";

        string ftpfullpath = ftpHost + "/" + "OutdoorTest.zip";

        string fileToUpload = @"c:\temp\Outdoorbilder.zip";
        try
        {

            FtpWebRequest request = (FtpWebRequest)WebRequest.Create(ftpfullpath);
            request.Method = WebRequestMethods.Ftp.UploadFile;

            request.Credentials = new NetworkCredential(ftpUser,ftpPassword);
            request.UseBinary = true;
            request.KeepAlive = false;
            request.ReadWriteTimeout = 1000000;
            request.Timeout = 1000000;

            using (Stream requestStream = request.GetRequestStream())
            {

                using (FileStream fs = File.OpenRead(fileToUpload))
                {
                    byte[] b = new byte[10 * 1024];
                    int readLength = 0;
                    int sentLength = 0;
                    while ((readLength = fs.Read(b, 0, b.Length)) > 0)
                    {
                        await requestStream.WriteAsync(b, 0, b.Length);
                        int percentComplete = (int)((float)(sentLength += readLength) / (float)fs.Length * 100);
                        ftpprogress.Value =  percentComplete;
                    }
                    requestStream.Close();
                    requestStream.Flush();
                }
            }

            FtpWebResponse response = (FtpWebResponse)request.GetResponse();
            response.Close();


            result = response.StatusDescription;
        }
        catch (WebException e)
        {

            result = e.Message;
            if (e.Status == WebExceptionStatus.ProtocolError)
            {
                result = result + "Status Code : " +
                    ((FtpWebResponse)e.Response).StatusCode;
                result = result + "\nStatus Description : " +
                    ((FtpWebResponse)e.Response).StatusDescription;
            }
        }
        catch (Exception e)
        {
            result = e.Message;
        }


        MessageBox.Show(result);
    }
}

代码似乎工作正常，我得到了226响应。但是ftp服务器上的zip文件比原始文件大约1000字节，并且下载到移动设备后无法打开/提取。

当我上传没有async / await模式时，上传的文件在ftp服务器上的大小与本地原始文件大小相同。

这种情况如何/在何处发生？

Answer 1

这与async / await无关。

您的问题是您没有告诉上传的正确尺寸。看看这两行：

while ((readLength = fs.Read(b, 0, b.Length)) > 0)
{
    await requestStream.WriteAsync(b, 0, b.Length);

您需要指定WriteAsyc写入读取量而不是为字节缓冲区分配的量。至少最后一次读取将返回小于缓冲区大小。

所以正确的代码是：

while ((bytesRead = fs.Read(b, 0, b.Length)) > 0)
{
    await requestStream.WriteAsync(b, 0, bytesRead);

async / await ftpupload会损坏上传的文件

1 个答案: