Question

我有以下基于SnakeYAML的代码（v1.17）：

public abstract class Beverage {
    protected int quantityOunces;

    // Getters, setters, ctors, etc.
}

public class AlcoholicBeverage extends Beverage {
    protected Double alcoholByVolume;

    // Getters, setters, ctors, etc.
}

public class SnakeTest {
    public static void main(String[] args) {
        new SnakeTest().serialize();
    }

    void serialize() {
        AlcoholicBeverage alcBev = new AlcoholicBeverage(20, 7.5);

        String alcYml = "/Users/myuser/tmp/alcohol.yml";

        FileWriter alcWriter = new FileWriter(alcYml);

        Yaml yaml = new Yaml();

        yaml.dump(alcBev, alcWriter);
    }
}

生成以下/Users/myuser/tmp/alcohol.yml文件：

!!me.myapp.model.AlcoholicBeverage {}

我原本希望文件的内容类似于：

quantityOunces: 20
alcoholByVolume: 7.5

所以我问：

如何让yaml.dump(...)将对象属性正确序列化到文件中？和
那个!!me.myapp.model.AlcoholicBeverage {}元数据很烦人......无论如何要配置Yaml忽略/忽略它？

Answer 1

您可以通过修改代码获得所需的输出，如下所示：

<强> SnakeTest.java

import java.io.FileWriter;
import java.io.IOException;

import org.yaml.snakeyaml.Yaml;

abstract class Beverage {
    protected int quantityOunces;

    public int getQuantityOunces() {
        return quantityOunces;
    }

    public void setQuantityOunces(int quantityOunces) {
        this.quantityOunces = quantityOunces;
    }

}

class AlcoholicBeverage extends Beverage {
    protected Double alcoholByVolume;

    public AlcoholicBeverage(int quatityOnces, double alcoholByVolume) {
        this.quantityOunces = quatityOnces;
        this.alcoholByVolume = alcoholByVolume;
    }

    public Double getAlcoholByVolume() {
        return alcoholByVolume;
    }

    public void setAlcoholByVolume(Double alcoholByVolume) {
        this.alcoholByVolume = alcoholByVolume;
    }

}

public class SnakeTest {
    public static void main(String[] args) throws IOException {
        new SnakeTest().serialize();
    }

    void serialize() throws IOException {
        AlcoholicBeverage alcBev = new AlcoholicBeverage(20, 7.5);

        String alcYml = "/Users/myuser/tmp/alcohol.yml";

        Yaml yaml = new Yaml();
        try (FileWriter alcWriter = new FileWriter(alcYml)) {
            alcWriter.write(yaml.dumpAsMap(alcBev));
        }

    }
}

代码已包含在具有以下内容的maven项目中的的pom.xml ：

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>SnakeYAML</groupId> <artifactId>SnakeYAML</artifactId> <version>0.0.1-SNAPSHOT</version> <dependencies> <dependency> <groupId>org.yaml</groupId> <artifactId>snakeyaml</artifactId> <version>1.17</version> </dependency> </dependencies> </project>

输出是：

alcoholByVolume: 7.5 quantityOunces: 20

获取SnakeYAML以正确序列化对象层次结构

1 个答案: