Question

有没有办法将try / except块中的异常从一个传播到下一个？

我想捕获一个特定的错误，然后进行一般的错误处理。

“raise”让异常“冒泡”到外部的try / except，但不会在引发错误的try / except块内部。

理想情况应该是这样的：

import logging

def getList():
    try:
        newList = ["just", "some", "place", "holders"]
        # Maybe from something like: newList = untrustedGetList()

        # Faulty List now throws IndexError
        someitem = newList[100]

        return newList

    except IndexError:
        # For debugging purposes the content of newList should get logged.
        logging.error("IndexError occured with newList containing: \n%s",   str(newList))

    except:
        # General errors should be handled and include the IndexError as well!
        logging.error("A general error occured, substituting newList with backup")
        newList = ["We", "can", "work", "with", "this", "backup"]
        return newList

我遇到的问题是当IndexError被第一个捕获时除外，我的第二个除了块之外的常规错误处理没有被应用。

我现在唯一的解决方法是在第一个块中包含一般错误处理代码。即使我把它包装在它自己的功能块中，它仍然看起来不那么优雅......

Answer 1

您有两种选择：

请勿使用专用IndexError块捕获except ..。您始终可以通过捕获BaseException并将例外分配给名称（此处为e）来手动测试常规块中的异常类型：

try:
    # ...
except BaseException as e:
    if isinstance(e, IndexError):
        logging.error("IndexError occured with newList containing: \n%s",   str(newList))

    logging.error("A general error occured, substituting newList with backup")
    newList = ["We", "can", "work", "with", "this", "backup"]
    return newList

使用嵌套的try..except语句并重新提升：

try:
    try:
        # ...
    except IndexError:
        logging.error("IndexError occured with newList containing: \n%s",   str(newList))
        raise
except:
    logging.error("A general error occured, substituting newList with backup")
    newList = ["We", "can", "work", "with", "this", "backup"]
    return newList

Python：通过具有多个Excepts的Try / Except块传播异常

1 个答案: