Question

int sum=0;
for ( int i=0; i < dataGridView1.Rows.Count; ++i)
{
   sum += int.Parse(dataGridView1.Rows[i].Cells[3].Value.ToString());
}
total.Text = sum.ToString();Value) 
//showing error Input string was not in a correct format.

我也试过sum += int.Parse(dataGridView1.Rows[i].Cells[3].Value.ToString()); 但仍显示错误。我甚至尝试过双重但仍然出错

请帮忙

Answer 1

问题很可能是你试图解析标题中的十进制数，但是你正在使用int.Parse函数。 int.Parse会失败，如果你给它一个＆＃39; 5.25＆＃39;您得到完全相同的错误消息的值：＆＃34;输入字符串的格式不正确＆＃34;。

您可以尝试使用decimal.Parse方法解析您的号码

int sum=0;
for ( int i=0; i < dataGridView1.Rows.Count; ++i)
{
    //this decimal cast to integer will ignore any numbers after the decimal point. 
    //e.g.: 0.6 will add 0 (absolutely nothing) to the sum variable. 
    //I would recommend using the other solution below.
    sum += (int)decimal.Parse(dataGridView1.Rows[i].Cells[3].Value.ToString(), System.Globalization.NumberStyles.Any);
}
total.Text = sum.ToString();

或将整数和一起更改为十进制类型

decimal sum = 0m;
for ( int i=0; i < dataGridView1.Rows.Count; ++i)
{
    sum += decimal.Parse(dataGridView1.Rows[i].Cells[3].Value.ToString(), System.Globalization.NumberStyles.Any);
}
total.Text = sum.ToString();

我想要对十进制值求和

1 个答案: