Question

我有一张这样的表：

table t1{ida,idb,idc}

我在tabletype变量

中有一个记录列表

table t2{idb,idc}

现在，我想检查是否存在t1与{i}所有t2相同的任何一组{id}

Answer 1

好像你想要这样的东西：

DECLARE @t1 TABLE ( ida INT, idb INT, idc INT )
DECLARE @t2 TABLE ( idb INT, idc INT )

INSERT  INTO @t1
VALUES  ( 1, 1, 1 ),
        ( 1, 2, 1 ),
        ( 1, 3, 2 ),
        ( 2, 1, 1 ),
        ( 2, 2, 1 ),
        ( 2, 1, 2 )

INSERT  INTO @t2
VALUES  ( 1, 1 ),
        ( 2, 1 ),
        ( 3, 2 )

SELECT DISTINCT
        t1.ida
FROM    @t1 t1
WHERE   NOT EXISTS ( SELECT *
                     FROM   @t2 t2
                     WHERE  NOT EXISTS ( SELECT *
                                         FROM   @t1
                                         WHERE  ida = t1.ida
                                                AND idb = t2.idb
                                                AND idc = t2.idc ) )
        AND NOT EXISTS ( SELECT *
                         FROM   @t1 tt1
                         WHERE  ida = t1.ida
                                AND NOT EXISTS ( SELECT *
                                                 FROM   @t2
                                                 WHERE  idb = tt1.idb
                                                        AND idc = tt1.idc ) )

输出：

ida
1

因此，除了相同匹配的数量之外，这仅返回完全匹配的ida个值。即以下内容仍然匹配：

( 1, 1, 1 ),
( 1, 2, 1 ),
( 1, 3, 2 ),
( 1, 3, 2 )

Answer 2

尝试以下查询，该查询使用inner join查找表t1和t2中的匹配行，并显示完全匹配的t1.ida值

select a.ida
from t1 a inner join t2 b 
on a.idb =  b.idb and a.idc = b.idc
group by a.ida 
having count(1) >= (select count(1) from t2)

比较列表SQL查询

2 个答案: