在实体中使用嵌入式类时,传递的已分离实体仍然存在

时间:2016-12-29 07:27:46

标签: java jpa persistence

因为,我正在阅读JPA(Java Persistence API)。我在那里读到了Embeddable Classes。所以,我试图在我的实体类中使用该概念。但在使用这个时,我面临着一个分离实体的问题。

这里我在Entity中有Embeddable Class(ZipCode)。

可嵌入班级

@Embeddable public class ZipCode {    
private String zip;    
private String plusFour; 

//getter & setter also.
}

实体类

@Entity
@Table(name = "address")
public class Address {

@Id
@GeneratedValue(strategy = IDENTITY)
private long id;

@Embedded
private ZipCode zipCode;

//getter & setter also.

}

我的持久性代码:

@WebServlet("/RegisterServlet")
public class RegisterServlet extends HttpServlet {
private static final long serialVersionUID = 1L;

@Inject
private CrudService crudService;

public RegisterServlet() {
    super();
}

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    response.getWriter().append("Served at: ").append(request.getContextPath());
}

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    ZipCode z = new ZipCode();
    z.setZip("bharti");
    z.setPlusFour("rawat");

    Address a = new Address();
    a.setId(1);
    a.setZipCode(z);

    try{
        crudService.create(a);

    }catch(Exception e){
        log.info("exception occurs "+ e.getMessage());
    }

}

}

我的CrudSrvice代码

@Stateless
@TransactionAttribute(TransactionAttributeType.REQUIRED)
public class CrudServiceImpl implements CrudService {   
@PersistenceContext(unitName = "localmedecube")
private EntityManager em;

public CrudServiceImpl() {
    // TODO Auto-generated constructor stub
}

@Override
public <T> T create(T t) {
    this.em.persist(t);
    this.em.flush();
    this.em.refresh(t);
    return t;
}

@Override
public void delete(@SuppressWarnings("rawtypes") Class type, Object id) {
    @SuppressWarnings("unchecked")
    Object ref = this.em.getReference(type, id);
    this.em.remove(ref);

}

@Override
public <T> T update(T t) {
    return this.em.merge(t);
}

}

当我尝试保留我的地址实体时,它会给我这样的错误

  

引起:javax.persistence.PersistenceException:org.hibernate.PersistentObjectException:传递给的分离实体   persist:model.Address

请告诉我为什么会出现此异常。并为我提供适当的答案。

1 个答案:

答案 0 :(得分:1)

如果您已使用Address保留了id = 1,那么您的代码就会中断。您必须为每个请求设置新的id

因为你已经使用

@GeneratedValue(strategy = IDENTITY)
private long id;

数据库应该为您设置ID。对此的先决条件是将字段id创建为自动增量字段。

例如,在MySQL创建时设置自动增量字段。

CREATE TABLE Persons
(
id int NOT NULL AUTO_INCREMENT,
<...>
PRIMARY KEY (ID)
)