我有一张员工时钟冲击表，看起来像这样：
| EmployeeID | PunchDate | PunchTime | PunchType | Sequence |
|------------|------------|-----------|-----------|----------|
| 5386 | 12/27/2016 | 03:57:42 | On Duty | 552 |
| 5386 | 12/27/2016 | 09:30:00 | Off Duty | 563 |
| 5386 | 12/27/2016 | 010:02:00 | On Duty | 564 |
| 5386 | 12/27/2016 | 12:10:00 | Off Duty | 570 |
| 5386 | 12/27/2016 | 12:22:00 | On Duty | 571 |
| 5386 | 12/27/2016 | 05:13:32 | Off Duty | 578 |
我需要做的是删除 Off Duty 打卡与以下 值班打卡之间差异的任何行不到25分钟。在上面的例子中，我想删除序列570和571。
我已经通过从另一个表中拉出所有 Off Duty 拳击并使用此查询拉出关闭之后的所有 On Duty 拳击来创建此表职责打孔：
SELECT * FROM [dbo].[Punches]
INSERT INTO [dbo].[UpdatePunches (EmployeeID,PunchDate,PunchTime,PunchType,Sequence)
SELECT * FROM [dbo].[Punches]
WHERE Sequence IN (
SELECT Sequence + 1
FROM [dbo].[Punches]
WHERE PunchType LIKE 'Off Duty%') AND
PunchType LIKE 'On Duty%'
我一直试图在这段代码中加入某种DATEDIFF查询，并作为一个单独的步骤去除这些，但没有任何运气。我不能使用特定的序列号，因为每次打卡都会改变。
我正在使用SQL Server 2008。
我们非常感谢任何建议。
答案 0 :(得分：2)
您可以根据punchdate和punchtime为每位员工分配rownumbers，并根据日期和时间的升序将每一行与下一行连接。
此后，获取差异小于25分钟的那些行的rownumbers，最后删除这些行。
with rownums as
(select t.*,row_number() over(partition by employeeid
order by cast(punchdate +' '+punchtime as datetime) ) as rn
from t)
,rownums_to_delete as
(
select r1.rn,r1.employeeid
from rownums r1
join rownums r2 on r1.employeeid=r2.employeeid and r1.rn=r2.rn+1
where dateadd(minute,25,cast(r2.punchdate +' '+r2.punchtime as datetime)) > cast(r1.punchdate +' '+r1.punchtime as datetime)
and r1.punchtype <> r2.punchtype
union all
select r2.rn, r2.employeeid
from rownums r1
join rownums r2 on r1.employeeid=r2.employeeid and r1.rn=r2.rn+1
where dateadd(minute,25,cast(r2.punchdate +' '+r2.punchtime as datetime)) > cast(r1.punchdate +' '+r1.punchtime as datetime)
and r1.punchtype <> r2.punchtype
)
delete r
from rownums_to_delete rd
join rownums r on rd.employeeid=r.employeeid and r.rn=rd.rn
如果日期和时间列不是varchar，而是实际date和time数据类型，请在查询中使用punchdate+punchtime。
编辑：查询的简单版本是
with todelete as (
select t1.employeeid,cast(t2.punchdate+' '+t2.punchtime as datetime) as punchtime,
t2.punchtype,t2.sequence,
cast(t1.punchdate+' '+t1.punchtime as datetime) next_punchtime,
t1.punchtype as next_punchtype,t1.sequence as next_sequence
from t t1
join t t2 on t1.employeeid=t2.employeeid
and cast(t2.punchdate+' '+t2.punchtime as datetime) between dateadd(minute,-25,cast(t1.punchdate+' '+t1.punchtime as datetime)) and cast(t1.punchdate+' '+t1.punchtime as datetime)
where t2.punchtype <> t1.punchtype
)
delete t
from t
join todelete td on t.employeeid = td.employeeid
and cast(t.punchdate+' '+t.punchtime as datetime) in (td.punchtime,td.next_punchtime)
;
答案 1 :(得分：2)
SQL Server有一个很好的称为可更新CTE的能力。使用lead()和lag()，您可以完全按照自己的意愿行事。以下假设日期实际存储为datetime - 这只是为了方便一起添加日期和时间（您还可以明确使用转换）：
with todelete as (
select tcp.*,
(punchdate + punchtime) as punchdatetime.
lead(punchtype) over (partition by employeeid order by punchdate, punchtime) as next_punchtype,
lag(punchtype) over (partition by employeeid order by punchdate, punchtime) as prev_punchtype,
lead(punchdate + punchtime) over (partition by employeeid order by punchdate, punchtime) as next_punchdatetime,
lag(punchdate + punchtime) over (partition by employeeid order by punchdate, punchtime) as prev_punchdatetime
from timeclockpunches tcp
)
delete from todelete
where (punchtype = 'Off Duty' and
next_punchtype = 'On Duty' and
punchdatetime > dateadd(minute, -25, next_punchdatetime)
) or
(punchtype = 'On Duty' and
prev_punchtype = 'Off Duty' and
prev_punchdatetime > dateadd(minute, -25, punchdatetime)
);
编辑：
在SQL Server 2008中，您可以使用相同的想法，但效率不高：
delete t
from t outer apply
(select top 1 tprev.*
from t tprev
where tprev.employeeid = t.employeeid and
(tprev.punchdate < t.punchdate or
(tprev.punchdate = t.punchdate and tprev.punchtime < t.punchtime)
)
order by tprev.punchdate desc, tprev.punchtime desc
) tprev outer apply
(select top 1 tnext.*
from t tnext
where tnext.employeeid = t.employeeid and
(t.punchdate < tnext.punchdate or
(t.punchdate = tnext.punchdate and t.punchtime < tnext.punchtime)
)
order by tnext.punchdate desc, tnext.punchtime desc
) tnext
where (t.punchtype = 'Off Duty' and
tnext.punchtype = 'On Duty' and
t.punchdatetime > dateadd(minute, -25, tnext.punchdatetime)
) or
(t.punchtype = 'On Duty' and
tprev.punchtype = 'Off Duty' and
tprev.punchdatetime > dateadd(minute, -25, t.punchdatetime)
);
答案 2 :(得分：1)
也许这样的东西很容易在那里拍打..这只是使用一个子查询找到下一个值班的＆＃39;打卡并在主要查询中将其与“关税”进行比较。冲。
Delete
FROM [dbo].[Punches] p
where p.PunchTime >=
dateadd(minute, -25, isnull (
(select top 1 p2.PunchTime from [dbo].[Punches] p2 where
p2.EmployeeID=p.EmployeeID and p2.PunchType='On Duty'
and p1.Sequence < p2.Sequence and p2.PunchDate=p.PunchDate
order by p2.Sequence asc)
),'2500-01-01')
and p.PunchType='Off Duty'
答案 3 :(得分：1)
您可以从CTE中的日期和时间字段创建日期时间，然后在关机时间之后查找下一个值班时间，如下所示：
;
WITH OnDutyDateTime AS
(
SELECT
EmployeeID,
Sequence,
DutyDateTime = DATEADD(ms, DATEDIFF(ms, '00:00:00', PunchTime), CONVERT(DATETIME, PunchDate))
FROM
#TempEmployeeData
where PunchType = 'On Duty'
),
OffDutyDateTime As
(
SELECT
EmployeeID,
Sequence,
DutyDateTime = DATEADD(ms, DATEDIFF(ms, '00:00:00', PunchTime), CONVERT(DATETIME, PunchDate))
FROM
#TempEmployeeData
where PunchType = 'Off Duty'
)
SELECT
OffDutyDateTime = DutyDateTime,
OnDutyDateTime = (SELECT TOP 1 DutyDateTime FROM OnDutyDateTime WHERE EmployeeID = A.EmployeeID AND Sequence > A.Sequence ORDER BY Sequence ASC ),
DiffInMinutes = DATEDIFF(minute,DutyDateTime,(SELECT TOP 1 DutyDateTime FROM OnDutyDateTime WHERE EmployeeID = A.EmployeeID AND Sequence > A.Sequence ORDER BY Sequence ASC ))
FROM
OffDutyDateTime A
OffDutyDateTime OnDutyDateTime DiffInMinutes
----------------------- ----------------------- -------------
2016-12-27 09:30:00.000 2016-12-27 10:02:00.000 32
2016-12-27 12:10:00.000 2016-12-27 12:22:00.000 12
2016-12-28 05:13:32.000 NULL NULL
（3行受影响）