Question

关于bash循环的this基本教程，我编写了以下脚本：

#!/bin/bash
# since Bash v4

i=16
max=256

while [  $i -le $max ]; do 
     echo $i
     let i=i*2
done

但是既然我觉得这很可怕（我是一个纯粹的while仇恨者），有没有办法写出类似的东西：

#!/bin/bash
# since Bash v4

start = 16
max = 256

for i in {start..max..i*2}
do
     echo $i
done

Answer 1

您可以使用<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <form id="form_vender"> <h1> Vender</h1> <select id="seleciona_Produto"> <option value="Uno">Uno</option> <option value="Duo">Duo</option> <option value="Trilogia">Trilogia</option> <option value="Cerveja">Cerveja</option> <option value="Refrigerante">Refrigerante</option> <option value="Fritas">Fritas</option> <option value="Água">Água</option> </select> <input type="text" size="3" placeholder="Qtde" id="quantidadeVenda"> <br /> <br /> </form> <input type="submit" onclick="addItem()" value="Adicionar item"> <input type="submit" onclick="FinalizaVenda()" value="Finalizar Venda"> <br /> <br /> <br /> <div id="tabelavenda" class="tabela"> <table> <thead> <tr> <th>Identificação</th> <th>Porte</th> </tr> </thead> </table> </div>循环：

for

给出这个输出：

for ((i = 16; i <= 256; i = i * 2)); do
  echo "$i"
done

for Bash for循环每次加倍步长值

1 个答案: