Question

我需要有关SQL Server如何将行值分配给具有相同ID的多行的帮助。为了说明，

Id = ProductInventoryCode
数量= QuantityInStock

ForDistribution ：

Id |   Qty  | TotalNoOfBranchesWithId
---+--------+-------------------------
1  |   40   |     2
2  |   33   |     3
3  |   21   |     2

将接收分发值

的表格

Id | BranchCode |    Qty | QtyFromForDistributionTable
-------------------------------------------------------
1       101          13            20
1       102           8            20
2       101          10            11
2       102           2            10
2       103           3            12
3       101           1            11
3       102          12            10

对于每个id和分支，分布应尽可能接近相等。

我得到了类似下面的东西，但有点迷茫和失去了道路。

with rs as 
(
    select 
        r.*, cume.cumequantity, 
        coalesce(s.shipped, 0) AS shipped
    from 
        tmpForDistribution r
    cross apply
        (SELECT SUM([QuantityInStock]) AS cumequantity
         FROM tmpForDistribution r2
         WHERE r2.ProductInventoryCode = r.ProductInventoryCode) cume 
    left join
        (SELECT ProductInventoryCode, COUNT(ProductInventoryCode) AS shipped
         FROM tmpDistributed s      
         GROUP BY s.ProductInventoryCode) s ON r.ProductInventoryCode = s.ProductInventoryCode      
)
select 
    rs.ProductInventoryCode, rs.cumequantity, rs.QuantityInStock,
    ***"how to distribute"***
from rs

我目前正在使用SQL Server 2008

这是一个示例屏幕输出

上面的结果是145分支，下面我们用来分配ForDistributionQty字段3130，我最后得到一个分数（DistVal = 21.586）这个问题不正确，它应该是一个整数，如然而，如果它只有21，那么21 x 145只是3045，这是85个单位。

Answer 1

在这里，我们分发价值观，然后进行最后的调整＆＃34;到具有最大数量（任意）的记录。但是在一天结束时，数学运算正常，分布式值也是正方形。

注意：不确定为什么在您的示例中为什么ID 2没有得到均匀分布

Declare @Table table (Id int,BranchCode int,Qty int)
Insert Into @Table values
(1,       101,          13),
(1,       102,           8),
(2,       101,          10),
(2,       102,           2),
(2,       103,           3),
(3,       101,           1),
(3,       102,          12)

Declare @Dist table (ID int,Qty int)
Insert Into @Dist values
(1,40),
(2,33),
(3,49)

;with cte0 as (
        Select A.*
              ,ToDist  = cast(D.Qty as int)
              ,DistVal = cast(D.Qty as int)/C.Cnt 
              ,RN      = Row_Number() over (Partition By A.ID Order By cast(D.Qty as int)/C.Cnt Desc,A.Qty Desc)
         From  @Table A
         Join  (Select ID,Cnt=count(*) from @Table Group By ID) C on A.ID=C.ID
         Join  @Dist D on A.ID=D.ID  )
, cte1 as (
        Select ID,AdjVal=Sum(DistVal)-max(ToDist) From cte0 Group By ID
)
Select A.ID
      ,A.BranchCode
      ,A.Qty
      ,DistVal = DistVal - case when A.RN<=abs(AdjVal) then 1*sign(AdjVal) else 0 end
 From cte0 A
 Join cte1 B on (A.ID=B.Id)
 Order By 1,2

返回

ID  BranchCode  Qty DistVal
1   101         13  20
1   102         8   20
2   101         10  11
2   102         2   11
2   103         3   11
3   101         1   24
3   102         12  25

Answer 2

如果你可以容忍十进制值，子查询似乎提供了一个更好的查询计划（在SQL 2014上测试，有一些合理的密钥，这可以避免表假脱机和一些额外的索引扫描）：

Declare @Table table (Id int,BranchCode int,Qty int, primary key(id, branchcode))
Insert Into @Table values
(1,       101,          13),
(1,       102,           8),
(2,       101,          10),
(2,       102,           2),
(2,       103,           3),
(3,       101,           1),
(3,       102,          12)

Declare @Dist table (ID int primary key,Qty int)
Insert Into @Dist values
(1,40),
(2,33),
(3,21)


SELECT
    t.id
   ,t.BranchCode
   ,t.Qty
   ,(d.Qty / CAST((SELECT COUNT(*) as cnt FROM @table t2 where t.id = t2.id) AS decimal(10,2))) as DistributedQty   
FROM @Table t
INNER JOIN @Dist d
ON d.id = t.Id

输出：

Id  BranchCode  Qty DistributedQty
1   101         13  20.00000000000
1   102         82  20.00000000000
2   101         10  11.00000000000
2   102         21  11.00000000000
2   103         31  11.00000000000
3   101         11  10.50000000000
3   102         12  10.50000000000

如果您需要将DistributedQty设为int并保留余数，那么我无法想到比@John Cappelletti更好的解决方案，并指出不均匀的数量可能不如确切地即使你可能希望（例如32分布为3将导致12/10/10分布而不是11/11/10分布）。

将值分配给SQL Server中的多个行

2 个答案: