Question

我在SQL Server 2014 Express上有这个SELECT：

SELECT DISTINCT Name, Lastname, Phone1, Phone2, Phone3, ... PhoneN
FROM TableX
WHERE Phone1 <> ''

现在结果如下：

Name  Lastname  Phone1     Phone2     Phone3     ...
James Brown     68798768
James Brown     98761456
Alice Grey      66687974
Peter Thompson  87997555
Peter Thompson  87997444
Peter Thompson  87997333

我需要一个SELECT，让我们回复一下那些同名的人的电话：

Name  Lastname  Phone1     Phone2     Phone3     ...
James Brown     68798768   98761456
Alice Grey      66687974
Peter Thompson  87997555   87997444   87997333

有任何疑问吗？

谢谢！

Answer 1

如果您拥有最大数量的手机并且不需要动态，那么条件聚合可能会有所帮助

Select Name
      ,LastName
      ,Phone1 = max(case when RN=1 then Phone1 else '' end)
      ,Phone2 = max(case when RN=2 then Phone1 else '' end)
      ,Phone3 = max(case when RN=3 then Phone1 else '' end)
      ,Phone4 = max(case when RN=4 then Phone1 else '' end)
From  (
        Select *
              ,RN = Row_Number() over (Partition By Name,LastName Order By Phone1)
        From  YourTable
       ) A
 Group By Name,LastName

Answer 2

考虑到您最多只有10个电话号码，您可以执行类似....

Select *
FROM (
       Select * 
          ,'Phone-' + CAST(ROW_NUMBER() OVER (PARTITION BY Name, LastName 
                        ORDER BY Phone1) AS VARCHAR(10)) PhoneNum
       FROM TableName
   ) t
PIVOT (MAX(Phone1)
       FOR PhoneNum
       IN ([Phone-1],[Phone-2],[Phone-3],[Phone-4],[Phone-5],
          [Phone-6],[Phone-7],[Phone-8],[Phone-9],[Phone-10])
       )p

加入一些具有相同代码的值

2 个答案: