Question

[System.Web.Services.WebMethod]  
public Array loaddata()    
string sql = "SELECT Name,Time,Inuse FROM table4";    
using (SqlConnection Connection = new SqlConnection((@"Data Source")))    
{    
    using (SqlCommand myCommand = new SqlCommand(sql, Connection))    
    {    
        Connection.Open();    
        using (SqlDataReader myReader = myCommand.ExecuteReader())    
        {    
            DataTable dt = new DataTable();    
            dt.Load(myReader);    
            Connection.Close();    
            DataView dv = new DataView(dt);    
            dv.RowFilter = (("Name='ACVX'"));    
            var tableEnumerable = dv.ToTable().AsEnumerable();     
            var tableArray = tableEnumerable.ToArray();    
            return tableArray ;   
        }    
    }    
}    

//Front End  

<html>  
<head/>  
<script>  
 PageMethods.loaddata(LoadSucc, LoadFail);  
           function LoadSucc(obj) //obj is array returned from back end{obj-tablearray]  
           {  
               var goog = [];  
               goog = Object.values(obj);  
            //I want load the obj into my array goog.  
           }  

           function LoadFail() {  
               alert("Data missing");  
           }  
script>  
<body/>  
<html>

我想将数据表内容加载到数组并使用页面方法将数组返回到前端。我尝试了一些东西但它不起作用。我的代码出了什么问题？
建议我一些想法

Answer 1

嗨尝试用这样的Jquery ajax函数调用你的web方法：

<html>  
<head/>  
<script>  



       $.ajax({
                                type: "POST",
                                url: "/yourpagename.aspx/loaddata",
                                data: "",
                                contentType: "application/json; charset=utf-8",
                                dataType: "json",
                                success: function (data) {
                                    var dataArray = $.map(data, function (item) {
                                        return item;
                                    });
                                    alert(dataArray);
                                    console.log(dataArray);
                                },
                                error: function (data) {
                                    alert("ajax error " + data);
                                }
                            });

script>  
<body/>  
<html>

从后端到前端返回阵列

1 个答案: