Question

到目前为止，我正在创建这样的终点：

@RequestMapping(value = "/test", method = RequestMethod.POST)
public @ResponseBody String indexPost(HttpServletRequest request, HttpServletResponse response)
    throws Exception {
//Doing calculations
return "Result";
}

但我想在服务器启动时到达application.properties，读出这样存储的数据：

methods: {
"endpointOne": "DBStoredProcedure1",
"endpointTwo": "DBStoredProcedure2"
}

所以当我的Spring Boot应用程序启动时，它将根据属性文件创建所有POST端点，其中包含第一个参数的名称（如＆＃34; endpointOne＆＃34;），以及将调用（并返回结果）存储过程定义为第二个参数（如＆＃34; DBStoredProcedure1＆＃34;）。

有可能吗？

Answer 1

是的，你可以。虽然目前尝试这样做有点不同。

最好使用“PathVariable” - 您可以在此处找到详细信息：

https://spring.io/guides/tutorials/bookmarks/

http://javabeat.net/spring-mvc-requestparam-pathvariable/

您在Controller类中的方法如下所示：

 @RequestMapping(value="/{endPoint}", method=RequestMethod.POST)
public String endPoint(@PathVariable String endPoint) {
   //Your endPoint is now the one what the user would like to reach
   //So you check if your property file contains this String - better to cache it's content
   //If it does, you call the service with the regarding Stored Procedure.
   String sPName = prop.getSPName(endPoint); //You need to implement it.
   String answer = yourService.execute(sPName);
   return answer; 
 }

显然你需要实现一个方法来处理那些在属性文件中找不到的查询，但是你明白了。

Answer 2

您可以在控制器中使用通配符“ / *”作为值。这样您的所有端点都可以使用相同的控制器请求方法。

下面是代码示例。

@RequestMapping(value = "/*", method = RequestMethod.GET, headers="Accept=*/*", produces = { "application/json" })
    public ResponseEntity<Object> getData(@RequestParam Map<String, String> reqParam, HttpServletRequest request)
            throws WriteException, IOException{

        MessageLogger.infoLog(EquityControllerImpl.class, GETQADTRSTOCKPRICELOGS,
                ENTRY);

        // Get Request URI
        MessageLogger.infoLog("Request URI: " + request.getRequestURI());
        String requestUri = request.getRequestURI();


        //Read all request parameters
        Map<String, String> requestParamMap = new HashMap<>();
        for (Map.Entry<String, String> param: reqParam.entrySet()
             ) {
            System.out.println("Parameter: " + param.getKey() + " ----> Value: " + param.getValue());
            requestParamMap.put(param.getKey(),param.getValue());
        }
}

您还可以定义静态swagger.json并在swagger配置中使用它。

    @Configuration
@EnableSwagger2
@Import(SpringDataRestConfiguration.class)
public class SwaggerConfig {

    @Bean
    public Docket api() {
        return new Docket(DocumentationType.SWAGGER_2)
                .select()
                .apis(RequestHandlerSelectors.basePackage("com.finance.dataplatform.*"))
                .apis(RequestHandlerSelectors.any())
                .paths(PathSelectors.any())
                .build().apiInfo(getApiInfo());
    }

    private ApiInfo getApiInfo() {
        return new ApiInfoBuilder().title("Investment Management").build();
    }

    private static Predicate<String> matchPathRegex(final String... pathRegexs) {
        return new Predicate<String>() {
            @Override
            public boolean apply(String input) {
                for (String pathRegex : pathRegexs) {
                    if (input.matches(pathRegex)) {
                        return true;
                    }
                }
                return false;
            }
        };
    }

    @Bean
    WebMvcConfigurer configurer () {
        return new WebMvcConfigurerAdapter() {
            @Override
            public void addResourceHandlers (ResourceHandlerRegistry registry) {
                registry.addResourceHandler("/config/swagger.json")
                        .addResourceLocations("classpath:/config");
            }
        };
    }


    @Primary
    @Bean
    public SwaggerResourcesProvider swaggerResourcesProvider(InMemorySwaggerResourcesProvider defaultResourcesProvider) {
        return () -> {
            SwaggerResource wsResource = new SwaggerResource();
            wsResource.setName("default");
            wsResource.setSwaggerVersion("2.0");
            wsResource.setLocation("/config/swagger.json");

            //List<SwaggerResource> resources = new ArrayList<>(defaultResourcesProvider.get());
            List<SwaggerResource> resources = new ArrayList<>();
            resources.add(wsResource);
            return resources;
        };
    }
}

Spring可以根据属性文件的内容动态创建端点吗？

2 个答案: