Question

我有行，有些行无法删除，因为它引用了其他表，另一行可以删除。

我想要的是删除可以删除的行并留下其他无法删除的行

到目前为止，我的代码是

$tkota = TbKota::find()->all();
            foreach($tkota as $kota){
                if($kota->delete()){
                    echo "del success<br/>";
                }else{
                    echo "fail ".$kota['api_id']."<br/>";
                }
            }

我上面的代码产生了这个错误

SQLSTATE[23503]: Foreign key violation: 7 ERROR: update or delete on table "tb_kota" violates foreign key constraint "fk_tb_produ_reference_tb_kota" on table "tb_produk_ekspedisi_by_vendor"
    DETAIL: Key (kota_id)=(1771) is still referenced from table "tb_produk_ekspedisi_by_vendor".
    The SQL being executed was: DELETE FROM "tb_kota" WHERE "kota_id"=1771

而不是在删除记录时显示成功，如果记录无法删除则显示失败。

我的代码出了什么问题？

提前感谢。

Answer 1

这个会更好

使用yii \ db \ IntegrityException;

使用yii \ web \ NotFoundHttpException;

  foreach($tkota as $kota){

  $connection = \Yii::$app->db;
  $transaction = $connection->beginTransaction();

  try {
          $kota->delete();
          $transaction->commit();
          return $this->redirect(['user/view', 'id' => $model->id]);

      }catch (IntegrityException $e) {

           $transaction->rollBack();
           throw new \yii\web\HttpException(500,"YOUR MESSAGE.", 405);


      }catch (\Exception $e) {

          $transaction->rollBack();
          throw new \yii\web\HttpException(500,"YOUR MESSAGE", 405);


    }

}

Answer 2

foreach($tkota as $kota){
     try {
        if($kota->delete()){
           echo "del success<br/>";
        }
     } catch (\Exception $e) {
        echo "fail ".$kota['api_id']."<br/>";
     }
}

如何处理删除时的完整性约束违规？

2 个答案: