Question

我有一个Raspberry Pi，我想在重新启动crontab时启动几个python脚本。我已经通过从终端调用python name_of_script.py手动成功运行每个脚本，但是当我通过crontab运行时，我会看到以下回溯。

Traceback (most recent call last):
  File "/home/pi/Desktop/photo_frames/becky/get_urls.py", line 11, in <module>
    driver = webdriver.Firefox()
  File "/usr/local/lib/python3.4/dist-packages/selenium/webdriver/firefox/webdriver.py", line 150, in __init__
    keep_alive=True)
  File "/usr/local/lib/python3.4/dist-packages/selenium/webdriver/remote/webdriver.py", line 92, in __init__
    self.start_session(desired_capabilities, browser_profile)
  File "/usr/local/lib/python3.4/dist-packages/selenium/webdriver/remote/webdriver.py", line 179, in start_session response = self.execute(Command.NEW_SESSION, capabilities)
  File "/usr/local/lib/python3.4/dist-packages/selenium/webdriver/remote/webdriver.py", line 236, in execute
    self.error_handler.check_response(response)
  File "/usr/local/lib/python3.4/dist-packages/selenium/webdriver/remote/errorhandler.py", line 192, in check_response raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.WebDriverException: Message: connection refused

任何关于诊断的指针都会非常感激，不幸的是我的Google-fu让我失望了。

Answer 1

对于Redhat / CentOS / Fedora，安装 Xvfb 和 pyvirtualdisplay

sudo yum install Xvfb
pip install pyvirtualdisplay

测试 Xvfb 和 pyvirtualdisplay ，不会出现异常

from pyvirtualdisplay import Display
display = Display(visible=0, size=(1024,768))
display.start()
display.stop()

附上您的Selenium代码

from pyvirtualdisplay import Display
display = Display(visible=0, size=(1024,768))
display.start()

driver = webdriver.Firefox()
driver.get(url)
driver.quit()

display.stop()

使用Crontab @reboot for python脚本时出现Selenium错误

1 个答案: