Question

我有500000个数值txt file.Couple of lines

  -938.549927    
  -938.542419    
  -938.534912    
  -938.523621    
  -938.523621    
  -938.512329    
  -938.512329    
  -938.523621    
  -938.519836    
  -938.523621    
  -938.519836    
  -938.508606    
  -938.508606    
  -938.508606    
  -938.519836    
  -938.531128    
  -938.538635

我想将它保存为csv文件。我试过这个

import csv

lines = [line.rstrip('\n') for line in open('d500.txt')]

myfile = open('n500.csv', 'wb')
wr = csv.writer(myfile, quoting=csv.QUOTE_ALL)
wr.writerow(lines)

我得到了这个

wc -l n500.csv
1 n500.csv

只是文件的一部分

358337    ","  -938.362061    ","  -938.369568    ","  -938.369568    ","  -938.369568    ","  -938.380859    ","  -938.377075    ","  -938.380859    ","  -938.373352    ","  -938.347046    ","  -938.343262    ","  -938.339539    ","  -938.324524    ","  -938.313232    ","  -938.328247    ","  -938.320740    ","  -938.320740    ","  -938.328247    ","  -938.324524    ","  -938.324524    ","  -938.316956

我真正想要的是这样的事情

 -938.316956   
 -938.316956   
 -938.313232

如果我尝试

wr.writerows(lines)

格式很疯狂

" "," ","-","9","3","8",".","3","1","3","2","3","2"," "," "," "," "
" "," ","-","9","3","8",".","3","2","8","2","4","7"," "," "," "," "
" "," ","-","9","3","8",".","3","2","0","7","4","0"," "," "," "," "
" "," ","-","9","3","8",".","3","2","0","7","4","0"," "," "," "," "
" "," ","-","9","3","8",".","3","2","8","2","4","7"," "," "," "," "
" "," ","-","9","3","8",".","3","2","4","5","2","4"," "," "," "," "
" "," ","-","9","3","8",".","3","2","4","5","2","4"," "," "," "," "
" "," ","-","9","3","8",".","3","1","6","9","5","6"," "," "," "," "
" "," ","-","9","3","8",".","3","1","3","2","3","2"," "," "," "," "
" "," ","-","9","3","8",".","3","1","3","2","3","2"," "," "," "," "
" "," ","-","9","3","8",".","3","0","9","4","4","8"," "," "," "," "
" "," ","-","9","3","8",".","3","1","6","9","5","6"," "," "," "," "
" "," ","-","9","3","8",".","3","1","6","9","5","6"," "," "," "," "
" "," ","-","9","3","8",".","3","1","3","2","3","2"," "," "," "," "

我的新代码版本

import csv

lines = [[line.rstrip('\n')] for line in open('d500.txt')]

myfile = open('n500.csv', 'wb')
wr = csv.writer(myfile, quoting=csv.QUOTE_ALL)
wr.writerows(lines)

比我得到

"  -938.324524    "
"  -938.313232    "
"  -938.328247    "
"  -938.320740    "
"  -938.320740    "
"  -938.328247    "
"  -938.324524    "
"  -938.324524    "
"  -938.316956    "
"  -938.313232    "
"  -938.313232    "
"  -938.309448    "
"  -938.316956    "
"  -938.316956    "
"  -938.313232    "

如何摆脱引号？

Answer 1

在循环中使用writeline

import csv

with open('n500.csv', 'wb') as myfile:
    wr = csv.writer(myfile)
    [wr.writerow(line.rstrip('\n')) for line in open('d500.txt')]

with语句处理文件关闭。

Answer 2

您所要做的就是将.txt重命名为.csv（或复制到.csv文件）。

由于只有一列，因此不需要（ c omma） s 操作符。

如何编写制作一列csv文件的Python代码？

2 个答案: