Question

我是新来的，也是编程的新手，所以在我的第一课我做了下面的代码，一切都很顺利，除了最后一个“总数武器”，当我在numberPistols中添加+1时没有更新。我知道numberPistols已更新，但在最后一行使用numberWeapons时，它不会显示新值。

我仍然无法理解为什么，有人可以向我解释并向我展示我做错了吗？

#include <iostream>
using namespace std;

int main() {
    int numberPistols = 5;
    int numberKnives = 18;
    int numberWeapons = numberPistols + numberKnives;

    cout << "Number of Pistols: " << numberPistols << endl;
    cout << "Number of Knives: " << numberKnives << endl;
    cout << "Total of Weapons: " << numberPistols + numberKnives << endl;

    cout << "There's a new Pistol available!" << endl;

    numberPistols = numberPistols + 1;
    cout << "New amount of Pistols " << numberPistols << endl;
    cout << "Updated total of Weapons " << numberWeapons << endl;

    return 0;
}

谢谢和最诚挚的问候！

Answer 1

正如Carcigenicate已经评论的那样，通常的方法是写一个函数

#include <iostream>
using namespace std;

int getNumberWeapons(int numberPistols, int numberKnives)
{
    return numberPistols + numberKnives;
}

int main() {
    int numberPistols = 5;
    int numberKnives = 18;

    cout << "Number of Pistols: " << numberPistols << endl;
    cout << "Number of Knives: " << numberKnives << endl;
    cout << "Total of Weapons: " << getNumberWeapons(numberPistols, numberKnives) << endl;

    cout << "There's a new Pistol available!" << endl;

    numberPistols = numberPistols + 1;
    cout << "New amount of Pistols " << numberPistols << endl;
    cout << "Updated total of Weapons " << getNumberWeapons(numberPistols, numberKnives) << endl;

    return 0;
}

更好的解决方案是上课。这可能会被夸大，但如果你想扩展你的“武器卡宾”，这将是合适的。它添加了几个成员函数来操作类的状态并获取它们的访问权。

#include <iostream>
using namespace std;

class WeaponCabinet
{
public:
    void setNumberPistols(int pistols)
    {
        numberPistols = pistols;
    }

    void setNumberKnives(int knives)
    {
        numberKnives = knives;
    }

    void addPistol()
    {
        ++numberPistols;
    }

    void addKnive()
    {
        ++numberKnives;
    }

    void removePistol()
    {
        if (numberPistols == 0) return;
        --numberPistols;
    }

    void removeKnive()
    {
        if (numberKnives == 0) return;
        --numberKnives;
    }

    int getNumberKnives()
    {
        return numberKnives;
    }

    int getNumberPistols()
    {
        return numberPistols;
    }

    int getNumberWeapons()
    {
        return numberKnives + numberPistols;
    }

private:
    int numberPistols;
    int numberKnives;
};

int main() {
    WeaponCabinet weaponCabinet;
    weaponCabinet.setPistols(5);
    weaponCabinet.setKnives(18);

    cout << "Number of Pistols: " << weaponCabinet.getNumberPistols() << endl;
    cout << "Number of Knives: " << weaponCabinet.getNumberKnives() << endl;
    cout << "Total of Weapons: " << weaponCabinet.getNumberWeapons() << endl;

    cout << "There's a new Pistol available!" << endl;

    weaponCabinet.addPistol();
    cout << "New amount of Pistols " <<  weaponCabinet.getNumberPistols() << endl;
    cout << "Updated total of Weapons " << weaponCabinet.getNumberWeapons() << endl;

    return 0;
}

通过这种方式，您可以直接连接刀具和手枪，并且不必每次都将它们传递给函数getNumberWeapons。

如果你不需要整个类处理你的武器，最现代的技术就是使用lambda（并且使用函数更接近解决方案）

#include <iostream>
using namespace std;

int main() {
    int numberPistols = 5;
    int numberKnives = 18;
    auto numberWeapons = [&numberPistols, &numberKnives]()
        {
            return numberPistols + numberKnives;
        };

    cout << "Number of Pistols: " << numberPistols << endl;
    cout << "Number of Knives: " << numberKnives << endl;
    cout << "Total of Weapons: " << numberWeapons() << endl;

    cout << "There's a new Pistol available!" << endl;

    numberPistols = numberPistols + 1;
    cout << "New amount of Pistols " << numberPistols << endl;
    cout << "Updated total of Weapons " << numberWeapons() << endl;

    return 0;
}

Answer 2

这可能不是你想要在你的第一堂C ++课程中学到的东西，但是如果你正在使用C ++ 11，你可以用一个lambda函数替换int numberWeapons，这会增加您调用时numberPistols和numberKnives的当前值：

  auto numberWeapons = [&numberPistols, &numberKnives]() {
    return numberPistols + numberKnives;
  };

numberWeapons现在是一个函数，可以从语句的numberPistol部分了解numberKnives和[&numberPistols, &numberKnives]变量。它不需要参数 - () - 它返回两个变量的总和。

（事实上()可以在这里省略，因为它们是空的，这个函数没有参数，但是我把它们留了下来，因为它使它更容易辨认作为lambda函数，通常看起来像[…](…){…}。）

#include <iostream>
using namespace std;

int main() {
  int numberPistols = 5;
  int numberKnives = 18;
  auto numberWeapons = [&numberPistols, &numberKnives]() {
    return numberPistols + numberKnives;
  };

  cout << "Number of Pistols: " << numberPistols << endl;
  cout << "Number of Knives: " << numberKnives << endl;
  cout << "Total of Weapons: " << numberWeapons() << endl; // outputs 23
  //                         note the brackets ^^

  cout << "There's a new Pistol available!" << endl;

  numberPistols = numberPistols + 1;
  cout << "New amount of Pistols " << numberPistols << endl;
  cout << "Updated total of Weapons " << numberWeapons() << endl; // outputs 24
  //                                                  ^^

  return 0;
}

Answer 3

写作时

int numberWeapons = numberPistols + numberKnives;

这不会创建一个＆＃34;等式＆＃34;每次更改后自动更新。这行在开头执行一次，因为没有循环，所以永远不会再执行。

您需要在更改后手动更新总计：

#include <iostream>
using namespace std;

int main() {
    int numberPistols = 5;
    int numberKnives = 18;
    int numberWeapons = numberPistols + numberKnives;

    cout << "Number of Pistols: " << numberPistols << endl;
    cout << "Number of Knives: " << numberKnives << endl;
    cout << "Total of Weapons: " << numberPistols + numberKnives << endl;

    cout << "There's a new Pistol available!" << endl;

    numberPistols = numberPistols + 1;
    //Manually update the variable. 
    numberWeapons = numberPistols + numberKnives;

    cout << "New amount of Pistols " << numberPistols << endl;
    cout << "Updated total of Weapons " << numberWeapons << endl;

    return 0;
}

请注意，除了int之外，它看起来就像它第一次设置一样，因为我不是声明 numberWeapons只是重新分配它。

真实＆＃34;程序，你使用一个处理更新的功能，但我认为这只会掩盖逻辑听力，因为你只是将2个数字加在一起。

Answer 4

变量彼此独立。为了向您解释，我们可以从苹果开始：

我给露西两个苹果。我给你三个苹果并说'＃34;我给你一个苹果加上我给露西的苹果数量。＆＃34;然后，过了一段时间，我又给露西送了一个苹果。你有几个苹果？

答案很简单：它是三个。就像C ++中的变量或任何其他编程语言一样，你和露西拥有的苹果数量是相互独立的。变量彼此独立。

变量值的变化不会影响另一个变量的值，即使您使用变量计算另一个变量的值也是如此。

如果您希望始终拥有更新的号码，该怎么办？

然后您必须每次计算值。程序员通常使用函数执行此操作。在您的示例中，我们可以将武器总数定义为返回numberPistols加numberKnives的函数。以下是我的表现：

#include <iostream> using namespace std; int main() { int numberPistols = 5; int numberKnives = 18; auto computeNumberWeapons = [&]{ return numberPistols + numberKnives; }; cout << "Number of Pistols: " << numberPistols << endl; cout << "Number of Knives: " << numberKnives << endl; cout << "Total of Weapons: " << numberPistols + numberKnives << endl; cout << "There's a new Pistol available!" << endl; numberPistols = numberPistols + 1; cout << "New amount of Pistols " << numberPistols << endl; cout << "Updated total of Weapons " << computeNumberWeapons() << endl; return 0; }

现在，computeNumberWeapons不是int类型的变量，而是一个计算前两个变量之和的函数。您必须使用()运算符调用该函数。

Answer 5

在这个程序中，所有语句都是按顺序执行的，每个语句只执行一次。 您必须重写或循环语句以重复。

int numberPistols = 5;
int numberKnives = 18;
int numberWeapons = numberPistols + numberKnives;

让我们对您的计划进行干预：

首先，您已声明整数类型变量numberPistols并使用值“5”初始化它。
然后，您已声明整数类型变量numberKnives并使用值“18”对其进行初始化。
在下一个语句中，您已声明变量numberWeapons并使用从numberPistols和numberKnives之和获得的值对其进行初始化。
打印完所有变量后，您将numberPistols的值增加1。

错误：

您已更新numberPistols但尚未更新numberWeapons。更改numberPistols或numberKnives的值不会影响numberWeapons的值，因为它已经存储，您必须使用新值更新存储的值以进行更改。

解决方案：

添加此行numberWeapons = numberPistols + numberKnives;

在numberPistols = numberPistols + 1;

之后

现在，您的最终代码将是：

#include <iostream>
using namespace std;

int main() {
    int numberPistols = 5;
    int numberKnives = 18;
    int numberWeapons = numberPistols + numberKnives;

    cout << "Number of Pistols: " << numberPistols << endl;
    cout << "Number of Knives: " << numberKnives << endl;
    cout << "Total of Weapons: " << numberPistols + numberKnives << endl;

    cout << "There's a new Pistol available!" << endl;

    numberPistols = numberPistols + 1;
    numberWeapons = numberPistols + numberKnives;         //update the numberWeapons here

    cout << "New amount of Pistols " << numberPistols << endl;
    cout << "Updated total of Weapons " << numberWeapons << endl;

    return 0;
}

Answer 6

我理解并尝试了一些人们在这里发布的不同代码，其中一个代码在我尝试编译和运行时给出了错误（下面是代码）。我使用的是Dev-C ++ 5.11。

int main() {

int numberPistols = 5;
int numberKnives = 18;
auto computeNumberWeapons = [&]{ return numberPistols + numberKnives; };

cout << "Number of Pistols: " << numberPistols << endl;
cout << "Number of Knives: " << numberKnives << endl;   
cout << "Total of Weapons: " << numberPistols + numberKnives << endl;   
cout << "There's a new Pistol available!" << endl;
numberPistols = numberPistols + 1;
cout << "New amount of Pistols " << numberPistols << endl;
cout << "Updated total of Weapons " << computeNumberWeapons()) << endl;
return 0;
}

有时候我使用的这个IDE +编译器会让我想一想，如果代码错误或者我在安装并在其中启动项目时做错了什么......

Error Image

Answer 7

好吧，如下所示，在int main（）

之前添加此函数

//function for calculating numberWeapons 
int totalWeapons(int numberPistols, int numberKnives){ 
     return numberPistols+numberKnives; 
}

并在下面的地方添加您想要更新的numberWeapons：

numberWeapons = totalWeapons(numberPistols, numberKnives);

即。你的代码就像：

#include <iostream>
using namespace std;

//function for calculating numberWeapons 
int totalWeapons(int numberPistols, int numberKnives){ 
     return numberPistols+numberKnives; 
}

int main() {
    int numberPistols = 5;
    int numberKnives = 18;
    int numberWeapons = totalWeapons(numberPistols, numberKnives); //call function here

    cout << "Number of Pistols: " << numberPistols << endl;
    cout << "Number of Knives: " << numberKnives << endl;
    cout << "Total of Weapons: " << numberWeapons << endl;

    cout << "There's a new Pistol available!" << endl;

    numberPistols = numberPistols + 1;

    //call function here to get updated numberWeapons
    numberWeapons = totalWeapons(numberPistols, numberKnives); 

    cout << "New amount of Pistols " << numberPistols << endl;
    cout << "Updated total of Weapons " << numberWeapons << endl;

    return 0;
}

C ++ - 变量未更新

7 个答案: