Question

我刚刚开始学习D3。现在我使用D3进行normalized stacked barchart。我的数据集与示例中给出的data.csv非常相似。只有7个类别，我只有2个。

我的问题是如何旋转xtick标签（例如设置为90度）？当标签文本很长时，它特别有用。

<!DOCTYPE html>
<meta charset="utf-8">
<style>

.bar {
  fill: steelblue;
}

.axis path {
  display: none;
}

</style>
<svg width="960" height="500"></svg>
<script src="//d3js.org/d3.v4.min.js"></script>
<script>

var svg = d3.select("svg"),
    margin = {top: 20, right: 60, bottom: 30, left: 40},
    width = +svg.attr("width") - margin.left - margin.right,
    height = +svg.attr("height") - margin.top - margin.bottom,
    g = svg.append("g").attr("transform", "translate(" + margin.left + "," + margin.top + ")");

var x = d3.scaleBand()
    .rangeRound([0, width])
    .padding(0.1)
    .align(0.1);

var y = d3.scaleLinear()
    .rangeRound([height, 0]);

var z = d3.scaleOrdinal()
    .range(["#9467BD","#ff6666"]);

var stack = d3.stack()
    .offset(d3.stackOffsetExpand);

d3.csv("data.csv", type, function(error, data) {
  if (error) throw error;

  data.sort(function(a, b) { return b[data.columns[1]] / b.total - a[data.columns[1]] / a.total; });

  x.domain(data.map(function(d) { return d.Group; }));
  z.domain(data.columns.slice(1));

  var serie = g.selectAll(".serie")
    .data(stack.keys(data.columns.slice(1))(data))
    .enter().append("g")
      .attr("class", "serie")
      .attr("fill", function(d) { return z(d.key); });

  serie.selectAll("rect")
    .data(function(d) { return d; })
    .enter().append("rect")
      .attr("x", function(d) { return x(d.data.Group); })
      .attr("y", function(d) { return y(d[1]); })
      .attr("height", function(d) { return y(d[0]) - y(d[1]); })
      .attr("width", x.bandwidth());

  g.append("g")
      .attr("class", "axis axis--x")
      .attr("transform", "translate(0," + height + ")")
      .call(d3.axisBottom(x));

  g.append("g")
      .attr("class", "axis axis--y")
      .call(d3.axisLeft(y).ticks(10, "%"));

  var legend = serie.append("g")
      .attr("class", "legend")
      .attr("transform", function(d) { var d = d[d.length - 1]; return "translate(" + (x(d.data.Group) + x.bandwidth()) + "," + ((y(d[0]) + y(d[1])) / 2) + ")"; });

  legend.append("line")
      .attr("x1", -6)
      .attr("x2", 6)
      .attr("stroke", "#000");

  legend.append("text")
      .attr("x", 9)
      .attr("dy", "0.35em")
      .attr("fill", "#000")
      .style("font", "10px sans-serif")
      .text(function(d) { return d.key; });
});

function type(d, i, columns) {
  for (i = 1, t = 0; i < columns.length; ++i) t += d[columns[i]] = +d[columns[i]];
  d.total = t;
  return d;
}

</script>

我尝试添加这段代码，但随后所有标签都消失了：

  g.append("g")
    .attr("class", "x axis")
    .attr("transform", "translate(0," + height + ")")
    .call(xAxis)
    .selectAll("text")
    .attr("y", 0)
    .attr("x", 10)
    .attr("dy", ".35em")
    .attr("transform", "rotate(90)")
    .style("text-anchor", "start");

更新：

Group,VAL 1,VAL 2
XXX XXXXXXXXXXXX,24983,66605
YYY XXXXXXXXXXXX,13522,61334
AAA XXXXXXXXXXXX,15289,37347
BBB XXXXXXXXXXXX,13155,38813
CCC XXXXXXXXXXXX,8374,22656
GGG XXXXXXXXXXXX,7660,21879
ABC XXXXXXXXXXXX,7935,16870
TTT XXXXXXXXXXXX,4831,18409
DDD XXXXXXXXXXXX,6301,16371
ZZZ XXXXXXXXXXXX,7207,13617
YYY XXXXXXXXXXXX,4407,15845
XX2 XXXXXXXXXXXX,3989,15031
FXX XXXXXXXXXXXXGC,3260,13754

如何在D3标准化堆叠条形图中旋转X刻度标签？

0 个答案: