Question

给定十进制数字我需要将其转换为二进制
给定二进制数我需要将其转换为十进制

转换后我需要对它执行一些操作（例如，添加）。另外，我需要以指定的宽度打印结果。

为了实现上述目的，我写了以下代码：

Binary-Decimal:

    n1 = int(input("Enter a binary number: "))
    n2 = int(input("Enter a binary number: "))

    # type cast to 'int' is done to provide width
    decimalN1 = int("{0:d}".format(n1), 2)
    decimalN2 = int("{0:d}".format(n2), 2)
    decimalSum = int("{0:d}".format(n1 + n2), 2)

    width = len(str(decimalSum))
    print("max width = {}".format(width))

    print ("{0:0{3}} + {1:0{3}} = {2:0{3}}".format(decimalN1, decimalN2, decimalSum, width))
    print ("{0} + {1} = {2}".format(type(decimalN1), type(decimalN2), type(decimalSum)))

Decimal-Binary:

    n1 = int(input("Enter a decimal number: "))
    n2 = int(input("Enter a decimal number: "))

    # type cast to 'int' is done to provide width
    binaryN1 = int("{0:b}".format(n1))
    binaryN2 = int("{0:b}".format(n2))
    binarySum = int("{0:b}".format(n1 + n2))

    width = (n1 + n2).bit_length()
    print("max width = {}".format(width))

    print ("{0:0{3}} + {1:0{3}} = {2:0{3}}".format(binaryN1, binaryN2, binarySum, width))
    print ("{0} + {1} = {2}".format(type(binaryN1), type(binaryN2), type(binarySum)))

有什么想知道还有其他（更好）的方法吗？我知道可以使用bin()函数，但是它返回一个字符串，所以我不能对它执行（整数）操作。

此外，任何评论意见改进代码将非常感激，因为我是Python的初学者。

Answer 1

这似乎正在做我想做的事情。以下代码是根据问题中提供的原始代码构建的，其中包含Code Review的建议，如建议的那样。

#!/usr/bin/python3

# this function accepts a decimal integer and returns a binary string
def decimalToBinary (decimalInt) :
    return "{0:b}".format (decimalInt)
# this function accepts a binary string and returns a decimal integer
def binaryToDecimal (binaryString) :
    return int (binaryString, 2)

x = int (input ("Enter a decimal number: "))
y = int (input ("Enter a decimal number: "))
sumInDecimal = x + y
print ("{0} when converted to binary is {1}".format (x, decimalToBinary(x)))
print ("{0} when converted to binary is {1}".format (y, decimalToBinary(y)))
print ("Addition in base 10: \t {0} + {1} = {2}".format (x, y, x + y))
print ("Addition in base  2: \t {0} + {1} = {2}".format (decimalToBinary(x), decimalToBinary(y), decimalToBinary(sumInDecimal)))
print ()
x = input ("Enter a binary number: ")
y = input ("Enter a binary number: ")
# convert binary to decimal before any operation, the result of the operation will be in decimal
sumInDecimal = binaryToDecimal(x) + binaryToDecimal(y)
print ("{0} when converted to decimal is {1}".format (x, binaryToDecimal(x)))
print ("{0} when converted to decimal is {1}".format (y, binaryToDecimal(y)))
print ("Addition in base  2: \t {0} + {1} = {2}".format (x, y, decimalToBinary(sumInDecimal)))
print ("Addition in base 10: \t {0} + {1} = {2}".format (binaryToDecimal(x), binaryToDecimal(y), sumInDecimal))

在Python中，十进制到二进制转换，反之亦然

1 个答案: