我尝试使用它,但有时候无法正常工作..我使用了一个while循环来循环代码。我可以为此添加一些列表器吗?任何人都可以给我正确答案吗?需要实时回应
while (true) {
msgList = new ArrayList<InboundMessage>();
Service.getInstance().readMessages(msgList, InboundMessage.MessageClasses.ALL);
for (InboundMessage im : msgList) {
if (last < im.getMemIndex()) {
ResultSet rs = DB.getConnection().createStatement().executeQuery("Select * From codes where code='" + im.getText() + "'");
if (rs.next()) {
ResultSet rs2 = DB.getConnection().createStatement().executeQuery("Select * From sms_log where code='" + im.getText() + "' AND tel_no='" + im.getOriginator() + "'");
if (rs2.next()) {
if (m == null) {
m = new SMSClient(1);
}
m.sendMessage(im.getOriginator(), "The Code is Already Sent... Thank You!.");
System.out.println("The Code is Already Sent... Thank You!.");
} else {
System.out.println("The Code Verified... Thank You!.");
if (m == null) {
m = new SMSClient(1);
}
m.sendMessage(im.getOriginator(), "The Code Verified... Thank You!.");
DB.getConnection().createStatement().execute("INSERT INTO sms_log (tel_no,code,status) values('" + im.getOriginator() + "','" + im.getText() + "',1)");
}
} else {
if (m == null) {
m = new SMSClient(1);
}
m.sendMessage(im.getOriginator(), "Invalid Code... Thank You!.");
System.out.println("Invalid Code... Thank You!.");
}
}
}
Thread.sleep(10000);
System.out.println("start");
}
答案 0 :(得分:0)
我认为IInboundMessageNotification是您正在寻找的界面
public class InboundNotification implements IInboundMessageNotification {
@Override
public void process(AGateway aGateway, Message.MessageTypes messageTypes, InboundMessage inboundMessage) {
//add you logic for received messages here
}
}
将通知类添加到smsLib服务
Service.getInstance().setInboundMessageNotification(new InboundNotification())
从现在开始,每次调制解调器收到消息时都会调用 process() 方法。
据我记忆,smslib(版本3.5.x)不会删除收到的邮件,因此需要手动完成
@Override
public void process(AGateway aGateway, Message.MessageTypes messageTypes, InboundMessage inboundMessage) {
try {
aGateway.deleteMessage(inboundMessage);
} catch (TimeoutException | GatewayException | InterruptedException | IOException e) {
e.printStackTrace();
}
// your logic here
}
否则,每次收到新消息时,您都会继续收到未删除的消息。
希望你会发现这很有用。