我只是想从我的应用程序中拨打电话。我尝试了其他一切。
我厌倦了互联网上的所有解决方案,包括mkyong,tutorialspoint等等。
phoneCalls.setOnClickListener(new View.OnClickListener() {
public void onClick(View arg0) {
Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:0377778888"));
if (ActivityCompat.checkSelfPermission(getActivity(),
Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
return;
}
startActivity(callIntent);
}
});
在我的清单中,我问了许可:
<uses-permission android:name="android.permission.CALL_PHONE"></uses-permission>
上面的代码也没有显示任何错误。我再次尝试了这个
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:0377778888"));
startActivity(callIntent);
}
});
}
尝试此代码时,它会在logcat中显示以下错误:
java.lang.SecurityException: Permission Denial: starting Intent { act=android.intent.action.CALL dat=tel:xxxxxxxxxx cmp=com.android.server.telecom/.components.UserCallActivity } from ProcessRecord{80f03c 26994:com.example.user.home/u0a73} (pid=26994, uid=10073) with revoked permission android.permission.CALL_PHONE
at android.os.Parcel.readException(Parcel.java:1620)
at android.os.Parcel.readException(Parcel.java:1573)
at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java:2680)
at android.app.Instrumentation.execStartActivity(Instrumentation.java:1509)
at android.app.Activity.startActivityForResult(Activity.java:3930)
at android.app.Activity.startActivityForResult(Activity.java:3890)
at android.app.Activity.startActivity(Activity.java:4213)
at android.app.Activity.startActivity(Activity.java:4181)
at com.example.user.home.Main3Activity$1.onClick(Main3Activity.java:30)
at android.view.View.performClick(View.java:5204)
at android.view.View$PerformClick.run(View.java:21158)
at android.os.Handler.handleCallback(Handler.java:739)
at android.os.Handler.dispatchMessage(Handler.java:95)
at android.os.Looper.loop(Looper.java:148)
at android.app.ActivityThread.main(ActivityThread.java:5461)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)
希望我在这里留下这个问题。有人请帮忙
答案 0 :(得分:4)
因为您在Marshmallow 6.0上尝试它并且您没有为Marshmallow或Android版本设置Runtime权限。
您的代码将在6.0以下但不在6.0或更高版本中运行。
按此重新编写代码。
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0)
{
callPhoneNumber();
}
});
}
使用权限检查创建此调用方法
public void callPhoneNumber()
{
try
{
if(Build.VERSION.SDK_INT > 22)
{
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
// TODO: Consider calling
ActivityCompat.requestPermissions(TestActivity.this, new String[]{Manifest.permission.CALL_PHONE}, 101);
return;
}
Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:" + "0377778888"));
startActivity(callIntent);
}
else {
Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:" + "0377778888"));
startActivity(callIntent);
}
}
catch (Exception ex)
{
ex.printStackTrace();
}
}
当用户授予权限时,控制权来自此处
@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions,
int[] grantResults)
{
if(requestCode == 101)
{
if(grantResults[0] == PackageManager.PERMISSION_GRANTED)
{
callPhoneNumber();
}
else
{
Log.e(TAG, "Permission not Granted");
}
}
}