$(document).on('click', '.content', function() {
... some other code ...
$.ajax({
type: 'POST',
url: '/includes/content.php',
data: info,
dataType: 'json',
success: function(result){
if(type == 'close') {
window.location.hash = '#' + hash;
location.reload();
}
}
});
return false;
});
首先我正在制作2乘3矩阵然后将其打印然后将其增加3乘4并且当试图到达数组[2] [0]时,我正在进行分段错误 问题是什么。我多次检查过但我找不到任何东西
答案 0 :(得分:1)
你的二维矩阵由指向一维int数组的指针表示。
该数组不是连续的二维数组。使用memcpy将旧数组复制到新数组,在函数增加中,不会起作用。
您必须遍历每个指针,然后通过指针指向的数组。基本上使用两个嵌套循环,就像打印数组时一样。
在函数增加中,代码不会释放指针数组所指向的数组:
free(array);
只释放指针数组,它还应该释放指针数组的每个元素。如果你看看如何分配数组,这是显而易见的:
array=(int**)malloc(sizeof(int*)*(*row));
for(i=0;i<(*row);++i){
array[i]=(int*)malloc(sizeof(int)*(*col));
}
答案 1 :(得分:1)
memcpy(temp,array,sizeof(int)*trow*tcol);
错了。
array
不是连续int
array
如下所示。
[int*][int*][int*]...
| |
| +-→[int][int][int]...
|
+-→[int][int][int]...
像这样修复
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
void print(int **array, int row, int col){
int i, j;
for(i = 0; i < row; ++i){
for(j = 0; j < col; ++j){
printf("%2d ", array[i][j]);
}
printf("\n");
}
}
int **take(int *row,int *col){
int **array, i;
printf("Enter the row number for array \n");
scanf("%d", row);
printf("Enter the column number for the array \n");
scanf("%d", col);
array = malloc(sizeof(int*) * (*row));
for(i = 0; i < (*row); ++i){
array[i] = calloc(*col, sizeof(int));
}
return array;
}
void assign(int **array,int row,int col){
int i,j;
srand(time(NULL));
for(i=0;i<row;++i){
for(j=0;j<col;++j){
array[i][j]=rand()%50;
}
}
}
int **increase(int **array, int *row, int *col){
int **temp, trow = *row, tcol = *col;
temp=take(row, col);
if(*row < trow || *col < tcol){
printf("Was decreased.\n");
for(int i = 0; i < *row; ++i)
free(temp[i]);
free(temp);
*row = trow; *col = tcol;
return array;//not change
}
for(int i = 0; i < trow; ++i){
memcpy(temp[i], array[i], sizeof(int) * tcol);
free(array[i]);
}
free(array);
return temp;
}
int main(void){
int **array = NULL;
int row, col;
array=take(&row, &col);
assign(array, row, col);
print(array, row, col);
array = increase(array, &row, &col);
//test: 2, 3 --> 3, 4
array[2][0] = 1;
print(array, row, col);
for(int i = 0; i < row; ++i)
free(array[i]);
free(array);
return 0;
}
答案 2 :(得分:0)
而不是memcpy
,realloc
可用于增加array
的大小。检查realloc和malloc的返回,因为它们可能会失败
还应检查scanf的返回,因为它也可能失败
而不是scanf,它使用fgets进行输入,并使用get_int_range
函数中的strtol解析输入。
使用realloc可以合并take
和increase
函数。由于take
函数现在知道旧的和新的尺寸,因此也可以包括assign
函数的操作。
takeaway
处理释放分配的内存。
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <time.h>
#include <errno.h>
#include <limits.h>
//inputs
// char *line : pointer to text to be parsed
// char **next : pointer to pointer to allow modification of caller's pointer
// char *delim : pointer to characters to be considered terminators
// int *value : pointer to int to allow modification of caller's int
// int min : minimum value of range
// int max : maximum value of range
// returns : 0 failure or 1 success
int get_int_range ( char *line, char **next, char *delim, int *value, int min, int max)
{
long int input = 0;
char *end = NULL;//will point to end of parsed value
if ( line == NULL) {
return 0;
}
errno = 0;
input = strtol ( line, &end, 10);//get the integer from the line. end will point to the end of the parsed value
if ( ( errno == ERANGE && ( input == LONG_MAX || input == LONG_MIN))
|| ( errno != 0 && input == 0)){// parsing error from strtol
perror ( "input");
return 0;
}
if ( end == line) {// nothing was parsed. no digits
line[strcspn ( line, "\n")] = '\0';//remove newline
printf ( "input [%s] MUST be a number\n", line);
return 0;// return failure
}
// *end is the character that end points to
if ( *end != '\0' && !( delim && strchr ( delim, *end))) {// is *end '\0' or is *end in the set of term characters
line[strcspn ( line, "\n")] = '\0';//remove newline
printf ( "problem with input: [%s] \n", line);
return 0;
}
if ( input < min || input > max) {// parsed value is outside of range
printf ( "input out of range %d to %d\n", min, max);
return 0;
}
if ( next != NULL) {// if next is NULL, caller did not want pointer to end of parsed value
*next = end;// *next allows modification to caller's pointer
}
if ( value == NULL) {
return 0;
}
*value = input;// *value allows modification to callers int
return 1;// success
}
void print(int **array,int row,int col){
int i,j;
for(i=0;i<row;++i){
for(j=0;j<col;++j){
printf("%d ",array[i][j]);
}
printf("\n");
}
}
int **take(int **array, int *row, int *col){
char line[256] = "";
int i;
int each = 0;
int newrow = 0;
int newcol = 0;
int valid = 0;
int **temp = 0;
int *temprow = 0;
do {
printf("Enter the row number for array \n");
fgets ( line, sizeof ( line), stdin);//read a line
valid = get_int_range ( line, NULL, "\n", &newrow, (*row) + 1, INT_MAX);// call to parse a value
} while ( !valid);
do {
printf("Enter the column number for the array \n");
fgets ( line, sizeof ( line), stdin);//read a line
valid = get_int_range ( line, NULL, "\n", &newcol, (*col) + 1, INT_MAX);// call to parse a value
} while ( !valid);
if ( ( temp = realloc ( array, sizeof( int*) * ( newrow))) == NULL) {
fprintf ( stderr, "problem reallocating\n");
return array;
}
array = temp;
for(i=0;i<(*row);++i){//realloc existing rows
if ( ( temprow = realloc ( array[i], sizeof ( int) * ( newcol))) == NULL) {
fprintf ( stderr, "problem reallocating row \n");
return array;
}
array[i] = temprow;
for ( each = *col; each < newcol; each++) {
array[i][each] = rand ( ) % 50;
}
}
for(i=(*row);i<newrow;++i){// malloc new rows
if ( ( array[i] = malloc ( sizeof ( int) * ( newcol))) == NULL) {
fprintf ( stderr, "problem allocating row \n");
return array;
}
for ( each = 0; each < newcol; each++) {
array[i][each] = rand ( ) % 50;
}
}
*row = newrow;
*col = newcol;
return array;
}
int **takeaway ( int **array, int *row, int *col) {//free allocated memory
*col = 0;
while ( *row){
*row -= 1;
free ( array[*row]);
}
free ( array);
return NULL;
}
int main(){
int **array=NULL;//so realloc will work on the first call
int row = 0;
int col = 0;
srand(time(NULL));//call srand once early in the program
array=take(array,&row,&col);
print(array,row,col);
array=take(array,&row,&col);
array[2][0] = 1;
print(array,row,col);
array = takeaway ( array, &row, &col);
return 0;
}