Question

我的文字看起来像这样：

TTL1 | TTL2 | TTL3
some text in a line1
some text in a line2
some text in a line3
TTL1 | TTL2 | 
TTL3
some text in a line1
some text in a line2
some text in a line3
some text in a line4
some text in a line5
TTL1 | TTL2 | TTL3
some text in a line1
some text in a line2
some text in a line3
some text in a line4
...

解释：我有标题行，有时可以分隔成多行，然后我有很多其他行。我希望捕获所有标题（即使它们在不同的行中），并且还在一个组中捕获标题之后的所有行。

我正在使用多行标题和多行内容，我不知道如何使用正则表达式和python来提取它。

和想法好吗？

Answer 1

你可以试试这个：

\s*(\w+)\s*\|\s*(\w+)\s*\|\s*(\w+)\s*\n([^\|]*)(?:\n|$)

根据op的评论，奇怪的是这些行可以包含|因此难以区分标题和行，因此可以尝试以下解决方案：

^\s*(\w+)\s*\|\s*(\w+)\s*\|\s*(\w+)\n(.*?)(?=^\s*\w+\s*\n*\|\s*\n*\w+\s*\n*\|\s*\n*\w+\s*\n*)|^\s*(\w+)\s*\|\s*(\w+)\s*\|\s*(\w+)\n(.*)$

Updated Regex Explanation

Explanation

示例代码：

import re

regex = r"\s*(\w+)\s*\|\s*(\w+)\s*\|\s*(\w+)\s*\n([^\|]*)(?:\n|$)"

test_str = ("TTL1 | TTL2 | TTL3\n"
    "some text in a line1\n"
    "some text in a line2\n"
    "some text in a line3\n"
    "TTL1 | TTL2 | \n"
    "TTL3\n"
    "some text in a line1\n"
    "some text in a line2\n"
    "some text in a line3\n"
    "some text in a line4\n"
    "some text in a line5\n"
    "TTL1 | TTL2 | TTL3\n"
    "some text in a line1\n"
    "some text in a line2\n"
    "some text in a line3\n"
    "some text in a line4")

matches = re.finditer(regex, test_str, re.DOTALL)

for matchNum, match in enumerate(matches):
  print(match.group(1))
  print(match.group(2))
  print(match.group(3))
  print(match.group(4))

Run it here

示例输出：

TTL1
TTL2
TTL3
some text in a line1
some text in a line2
some text in a line3
TTL1
TTL2
TTL3
some text in a line1
some text in a line2
some text in a line3
some text in a line4
some text in a line5
TTL1
TTL2
TTL3
some text in a line1
some text in a line2
some text in a line3
some text in a line4

Answer 2

对re.findall()函数使用以下方法：

# lines.txt is a file containing the initial text from your question 
with open('lines.txt', 'r') as fh:
    t = fh.read()
    items = re.findall(r'([A-Z\d\s|]+)([^A-Z]+)', t)

# 'h' contains header, 'lines' contains the lines related to current header 
for h, lines in items:
    print(h.replace('\n', ' '), lines, sep='\n')

输出：

TTL1 | TTL2 | TTL3 
some text in a line1
some text in a line2
some text in a line3

TTL1 | TTL2 | TTL3 
some text in a line1
some text in a line2
some text in a line3
some text in a line4
some text in a line5

TTL1 | TTL2 | TTL3 
some text in a line1
some text in a line2
some text in a line3
some text in a line4

Python推进正则表达式

2 个答案: