PS:请忽略中心的错误。
只需更新代码并设法解决 019 问题并循环遍历所有图像一次。但是,仍然无法在一个页面上显示3个图像。
以前设法在css {display}的帮助下显示我想要的内容 和JavaScript显示/隐藏功能,但不知道如何处理PHP。
$productArr = ["ac" => ["001" => ["dimension"=>"H: 85 W: 67 D: 72", "price"=>850.00 , "images"=>7],
"002" => ["dimension"=>"H: -- W: -- D: --", "price"=>860.00 , "images"=>7],
"003" => ["dimension"=>"H: 95 W: 71 D: 90", "price"=>890.00 , "images"=>7],
"004" => ["dimension"=>"H: 78 W: 68 D: 78", "price"=>740.00 , "images"=>4],
"005" => ["dimension"=>"H: 102 W: 69 D: 90", "price"=>890.00 , "images"=>7],
"006" => ["dimension"=>"H: 89 W: 80 D: 86", "price"=>1280.00, "images"=>7],
"007" => ["dimension"=>"H: 78 W: 66 D: 66", "price"=>680.00 , "images"=>7],
"008" => ["dimension"=>"H: 80 W: 78 D: 74", "price"=>800.00 , "images"=>7],
"009" => ["dimension"=>"H: 94 W: 64 D: 88", "price"=>790.00 , "images"=>5],
"010" => ["dimension"=>"H: 83 W: 68 D: 72", "price"=>850.00 , "images"=>7],
"011" => ["dimension"=>"H: 70 W: 66 D: 77", "price"=>860.00 , "images"=>7],
"012" => ["dimension"=>"H: 88 W: 84 D: 88", "price"=>1280.00, "images"=>7],
"013" => ["dimension"=>"H: 80 W: 70 D: 84", "price"=>860.00 , "images"=>7],
"014" => ["dimension"=>"H: 82 W: 68 D: 80", "price"=>780.00 , "images"=>7],
"015" => ["dimension"=>"H: 82 W: 72 D: 78", "price"=>890.00 , "images"=>7],
"016" => ["dimension"=>"H: 75 W: 59 D: 47", "price"=>780.00 , "images"=>7],
"017" => ["dimension"=>"H: 90 W: 77 D: 83", "price"=>1280.00, "images"=>7],
"018" => ["dimension"=>"H: -- W: -- D: --", "price"=>680.00 , "images"=>5],
"020" => ["dimension"=>"H: 74 W: 63 D: 89", "price"=>860.00 , "images"=>4]]
$catCode = $_GET['cat'];
$arr=[];
foreach ($productArr[$catCode] as $imgNumber => $productDetail) {
array_push($arr,$imgNumber);
$imgNumber = $arr;
// index[18] change to 20
}
echo"<div align='center'>
<ul class='pagination'>";
for ($i = 1; $i < count($productArr[$catCode]) / 3 + 1; $i++) {
echo"<li><a href='http://localhost/ca1/collectionPage.php?cat={$catCode}&page={$i}'> {$i}</a></li>
";
}
echo"<li><a href='http://localhost/ca1/collectionSummary.php?cat={$catCode}'>view all</a></li>";
echo"</ul>
</div>";
for($i=0; $i < count($productArr[$catCode]); $i++){
echo "<div class='col-md-4'>
<div class='thumbnail'>
<img class='img-responsive image_size' src='images/$catCode/row_{$catCode}{$arr[$i]}_m0.jpg'>
<div class='caption'>
<p align='center'><b>Model No.Row-{$upperCatCode}-{$arr[$i]}</b></p>
</div>
</div>
</div> ";
}
答案 0 :(得分:0)
您可以限制索引显示哪些图片,但是您需要将值 FROM 和 TO 发送到php脚本并添加如下的循环:< / p>
if(($i>$FROM)||($i<=$TO))
{
// Show the image
}
如果您将使用已显示的循环。