目前,我正在使用分页代码,并且它会连续显示所有页面
<div class="col-md-12">
<nav aria-label="Page navigation">
<ul class="pagination">
<?php for ($i=0 ; $i < $products->totalPages; $i++) : ?>
<li <?php if ($products->number == $i) echo "class='active'"; ?>>
<a <?php if ($products->number != $i): ?> href="index.php?page=<?php echo $i . (isset($_GET['cid']) ? '&cid=' . $_GET['cid'] : ''); ?>#prdct" <?php endif; ?>><?php echo($i + 1); ?></a>
</li>
<?php endfor; ?>
</ul>
</nav>
</div>
怎么做才能让它排成一排?
答案 0 :(得分:1)
您可以使用自己的逻辑来实现。根据当前页面和总页数生成有限数量的链接。
例如:
<div class="col-md-12">
<nav aria-label="Page navigation">
<ul class="pagination">
<li <?php if ($products->number == 0) echo "class='active'"; ?>>
<a <?php if ($products->number != 0): ?> href="index.php?page=0<?php echo(isset($_GET['cid']) ? '&cid=' . $_GET['cid'] : ''); ?>#prdct" <?php endif; ?>>1</a>
</li>
<?php if ($products->totalPages > 2) { ?>
<?php if ($products->number > 3): ?><li><a href="javascript:void(0)">...</a></li><?php endif; ?>
<?php for ($i = ($products->number == 0 ? 1 : $products->number-1); $i < $products->number+2 && $i < $products->totalPages - 1; $i++) { ?>
<li <?php if ($products->number == $i) echo "class='active'"; ?>>
<a <?php if ($products->number != $i): ?> href="index.php?page=<?php echo $i . (isset($_GET['cid']) ? '&cid=' . $_GET['cid'] : ''); ?>#prdct" <?php endif; ?>><?php echo($i + 1); ?></a>
</li>
<?php } ?>
<?php if ($products->number < $products->totalPages - 3): ?><li><a href="javascript:void(0)">...</a></li><?php endif; ?>
<?php } ?>
<?php if ($products->totalPages > 1): ?>
<li <?php if ($products->number == $products->totalPages) echo "class='active'"; ?>>
<a <?php if ($products->number != $products->totalPages - 1): ?> href="index.php?page=<?php echo ($products->totalPages - 1) . (isset($_GET['cid']) ? '&cid=' . $_GET['cid'] : ''); ?>#prdct" <?php endif; ?>><?php echo $products->totalPages; ?></a>
</li>
<?php endif; ?>
</ul>
</nav>
</div>