未定义的变量:pdo,在null上调用成员函数prepare()

时间:2016-12-26 23:09:22

标签: php mysql pdo

我正在关注视频并仔细检查所有代码,所有内容似乎都相同,但我收到了这些错误。

错误

注意:未定义的变量:第14行的QueryBuilder.php中的pdo

致命错误:在第14行的QueryBuilder.php中调用null上的成员函数prepare()

QueryBuilder.php

class QueryBuilder
{
    protected $pdo;

    public function __construct($pdo)
    {
        $this->pdo = $pdo;
    }

    public function selectAll($table)
    {
        $query = $pdo->prepare("SELECT * FROM `$table`"); // --> LINE 14 <--
        $query->execute();
        return $query->fetchAll();
    }
}

Connection.php

class Connection
{
    public static function make()
    {
        $servername = "localhost";
        $dbUsername = "root";
        $dbPassword = "";
        $dbName = "test";

        try {
            $pdo = new PDO("mysql:host=$servername;dbname=$dbName", $dbUsername, $dbPassword);
            $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
            $pdo->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
            return $pdo;
        }
        catch(PDOException $e){
            die($e->getMessage());
        }
    }
}

的init.php

require "database/Connection.php";
require "database/QueryBuilder.php";
require "app/Product.php";

$query = new QueryBuilder(Connection::make());

1 个答案:

答案 0 :(得分:2)

正如评论中所述,在OOP中,您需要使用$this->pdo传递对象的属性,而不是变量$query = $pdo->,因为您已经构建了&#39;编辑:

public function __construct($pdo)
{
    $this->pdo = $pdo;
    ^^^^^^^^^^
}

即:

$query = $this->pdo->prepare