Question

我是XMLdeserialization的新手。我使用xsd.exe生成对象类，以便对现有XML文件执行反序列化。当我在下面运行我的解决方案时，我收到错误

System.InvalidOperationException：＆lt;的xmlns =＆＃39;＆＃39;＆GT;没想到

on＆＃34; s =（NewDataSet）xs.Deserialize（sr）＆＃34;呼叫。我在Stackoverflow上看到了这个错误，每个人都说它在XMLRootAttribute行中。

[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]

我已尝试过对这一行的各种修复，但没有任何作用。有人可以纠正它或指向我的一些文档，解释如何纠正它？非常感谢先进。

另外，为什么xsd.exe首先生成正确的XmlRootAttribute行？我调用这个实用程序错了吗？或者是否存在xsd.exe实用程序无法处理的某些情况？

public class Program
{
    static void Main(string[] args)
    {
        SortedSet<string> symbolsEstablished = new SortedSet<string>();

        GetXmlDataSet("Expt 2buy.xml", ref symbolsEstablished);
    }

    public static void GetXmlDataSet(string fileName, ref SortedSet<string> symbols)
    {
        XmlSerializer xs = new XmlSerializer(typeof(NewDataSet));
        StreamReader sr = new StreamReader(@"C:\Users\mehl\AppData\Roaming\Fidelity Investments\WealthLabPro\1.0.0.0\Data\DataSets\" + fileName);
        NewDataSet s = (NewDataSet)xs.Deserialize(sr);
        Console.WriteLine(s.Items[0].DSString);
        sr.Close();
    }

    [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
    [System.SerializableAttribute()]
    [System.Diagnostics.DebuggerStepThroughAttribute()]
    [System.ComponentModel.DesignerCategoryAttribute("code")]
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
    public partial class DataSet
    {
        private string nameField;
        private string scaleField;
        private string barIntervalField;
        private string dSStringField;
        private string providerNameField;

        [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
        public string Name
        {
            get { return this.nameField; }
            set { this.nameField = value; }
        }

        [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
        public string Scale
        {
            get { return this.scaleField; }
            set { this.scaleField = value; }
        }

        [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
        public string BarInterval
        {
            get { return this.barIntervalField; }
            set { this.barIntervalField = value; }
        }

        [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
        public string DSString
        {
            get { return this.dSStringField; }
            set { this.dSStringField = value; }
        }

        [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
        public string ProviderName
        {
            get { return this.providerNameField; }
            set { this.providerNameField = value; }
        }
    }

    [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
    [System.SerializableAttribute()]
    [System.Diagnostics.DebuggerStepThroughAttribute()]
    [System.ComponentModel.DesignerCategoryAttribute("code")]
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
    public partial class NewDataSet
    {
        private DataSet[] itemsField;

        [System.Xml.Serialization.XmlElementAttribute("DataSet")]
        public DataSet[] Items
        {
            get { return this.itemsField; }
            set { this.itemsField = value; }
        }
    }
}

整个上面的代码段都包含在screener2wl命名空间中。

这是我尝试反序列化的XML文件：

<?xml version="1.0"?>
<DataSet xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Name>Expt 2buy</Name>
  <Scale>Daily</Scale>
  <BarInterval>0</BarInterval>
  <DSString>AAL,AFSI,BEN,BIG,BLKB,CDK,COHR,CRUS,EGP,EPE,ETH,FB,HUM,LSTR,MDP,MSI,NYT,TAST,TER,TSO,TXN,UTHR,VASC,VLO,WRI,</DSString>
  <ProviderName>FidelityStaticProvider</ProviderName>
</DataSet>

Answer 1

使用xml linq：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENAME);

            DataSet ds = doc.Descendants("DataSet").Select(x => new DataSet() {
                nameField = (string)x.Element("Name"),
                scaleField = (string)x.Element("Scale"),
                barIntervalField = (string)x.Element("BarInterval"),
                dSStringField = (string)x.Element("DSString"),
                providerNameField = (string)x.Element("ProviderName")
            }).FirstOrDefault();
        }
    }
    public partial class DataSet
    {
        public string nameField { get; set; }
        public string scaleField { get; set; }
        public string barIntervalField { get; set; }
        public string dSStringField { get; set; }
        public string providerNameField { get; set; }
    }
}

Answer 2

我开始思考...... xsd.exe是否会提供代码生成的解决方案来定义两个独立的 XmlRootAttribute节点？ XML文件甚至可以有两个根节点吗？也许xsd.exe生成的解决方案不应该太字面意思。： - ）

所以在编辑了它的解决方案之后，删除了一个定义了第二个XmlRootAttribute的部分，我得到了下面的解决方案，它可以工作。

namespace screener2wl
{
    public class Program
    {
        static void Main(string[] args)
        {
            SortedSet<string> symbolsEstablished = new SortedSet<string>();
            GetXmlDataSet("Expt 2buy.xml", ref symbolsEstablished);
        }

        public static void GetXmlDataSet(string fileName, ref SortedSet<string> symbols)
        {
            XmlSerializer xs = new XmlSerializer(typeof(DataSet));
            StreamReader sr = new StreamReader(@"C:\Users\mehl\AppData\Roaming\Fidelity Investments\WealthLabPro\1.0.0.0\Data\DataSets\" + fileName);
            DataSet s = (DataSet)xs.Deserialize(sr);
            Console.WriteLine(s.DSString);
            sr.Close();
        }

        [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
        [System.Xml.Serialization.XmlRootAttribute(IsNullable = false)]
        public class DataSet
        {
            private string nameField;
            private string scaleField;
            private string barIntervalField;
            private string dSStringField;
            private string providerNameField;

            [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
            public string Name
            {
                get { return this.nameField; }
                set { this.nameField = value; }
            }

            [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
            public string Scale
            {
                get { return this.scaleField; }
                set { this.scaleField = value; }
            }

            [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
            public string BarInterval
            {
                get { return this.barIntervalField; }
                set { this.barIntervalField = value; }
            }

            [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
            public string DSString
            {
                get { return this.dSStringField; }
                set { this.dSStringField = value; }
            }

            [System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
            public string ProviderName
            {
                get { return this.providerNameField; }
                set { this.providerNameField = value; }
            }
        }
    }
}

最重要的是，使用xsd.exe生成的代码解决方案从您的XML数据文件中作为指导，而不是事实。这是一个很好的工具，但需要与一粒盐一起使用。 ...欢迎您对我的XMLdeserialization问题发表评论。

在C＃反序列化期间，获取System.InvalidOperationException：＆lt;的xmlns =＆＃39;＆＃39;＆GT;没想到

2 个答案: