Pygame得分 - 打开和写入文件

时间:2016-12-26 19:25:11

标签: python pygame

我的游戏有问题,让我们说游戏中的得分为3,然后我尝试写出高于10的分数。它没有写出我试图修复的文件但它没有工作..请帮忙。以下只是代码的一部分

# Variables within loop
loop = True
over = False
# car
carx = int(display_w/2 - 20)
cary = 500
carwidth = 40
carheight = 70
cxchange = 0
# obstacle
obx = carx - carwidth
oby = -200
obwidth = random.randint(200, 450)
obheight = random.randint(100, 200)
obychange = 0
obstacle_speed = 7
# score appending
readhighscore = open("score.txt", "r")
highscore = readhighscore.read()
while loop:
    if over == True:
        message_to_screen("Game over!", black, -200, "large")
        message_to_screen("Final Score: " + str(score), black, -130, "small")
        fire_explosion(carx + int(carwidth / 2), cary)
        if str(score) > str(highscore):
            writehighscore = open("score.txt", "w")
            writehighscore.write(str(score))
        pygame.display.update()
    while over:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                quit()

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()
        elif event.type == pygame.KEYDOWN:
            if event.key == pygame.K_RIGHT:
                cxchange += 4
            elif event.key == pygame.K_LEFT:
                cxchange -= 4
        elif event.type == pygame.KEYUP:
            if event.key == pygame.K_RIGHT:
                cxchange = 0
            elif event.key == pygame.K_LEFT:
                cxchange = 0
    # Movement
    carx += cxchange
    oby += obychange
    obychange = obstacle_speed
# If Statements
    # end of map and if the car successfully dodges the obstacle
    if carx >= display_w - carwidth:
        carx = display_w - carwidth
    elif carx <= 0:
        carx = 0
    if oby > display_h:
        if score > 16:
            obwidth = random.randint(300, 450)
        else:
            obwidth = random.randint(200, 450)
        obx = carx - random.randint(0, 100)
        oby = random.randint(-1000, -500)
        score += 3
    # obstacle collision with the car
    if oby+obheight >= cary and oby <= cary+carheight:
        if carx+carwidth >= obx and carx <= obx + obwidth:
            over = True
            obychange = 0
    # score concept
    print(highscore)
# Drawing
    # background color
    gameDisplay.fill(white)
    # car
    gameDisplay.blit(car1, [carx, cary])
    # obstacle
    drawobjects(obx, oby, obwidth, obheight, blue)
    # score
    drawScore(score)
    pygame.display.update()
    clock.tick(FPS)

2 个答案:

答案 0 :(得分:1)

New Anwser: 对不起,我有点不活跃,但无论如何...... 问题出在这一行:

if str(score) > str(highscore):

或者,换句话说,您正在比较字符串。而不是str,做int,你会没事的。在这种情况下你不能比字符串更大的原因是复杂的。但如果您想要解释,请参阅:String Comparison Technique Used by Python

答案 1 :(得分:0)

以下代码应完全适用,但我不太清楚问题是什么。

with open("score.txt", "w") as f:
    f.write(str(score))

这只是我的头脑。
编辑:还有很多不必要的代码。阅读https://stackoverflow.com/help/mcve,关键字为 minimal