Question

我正在进行ajax调用以检索从查询返回的JSON数据。我的JSON正在返回以下内容（准确地说）：

[{
    "label": "",
    "value": "2302"
}, {
    "label": "9 - Contract set-up in EPICOR",
    "value": "2280"
}, {
    "label": "2 - Verify PO received",
    "value": "2279"
}, {
    "label": "7 - Review quote and prepare team for meeting",
    "value": "2281"
}]

但我需要它才能真正回归：

{
    "options": {
        "logan_dvprTasks.taskID": {
            [{
                "label": "",
                "value": "2302"
            }, {
                "label": "9 - Contract set-up in EPICOR",
                "value":"2280"
            }, {
                "label": "2 - Verify PO received",
                "value":"2279"
            }, {
                "label": "7 - Review quote and prepare team for meeting",
                "value":"2281"
            }]
        }
    }

我生成JSON的代码是：

public IEnumerable<updatetasks> GetAllItems(string dvprid)
{
    string stringSQL = "sqlStatement goes here";

    string connString = ConfigurationManager.ConnectionStrings["loganWebConn"]
                                            .ConnectionString;

    using (SqlConnection sqlConnection = new SqlConnection(connString))
    {
        sqlConnection.Open();

        using (SqlCommand cmd = sqlConnection.CreateCommand())
        {
            cmd.CommandText = stringSQL;
            cmd.CommandType = CommandType.Text;

            using (SqlDataReader reader = cmd.ExecuteReader())
            {
                while (reader.Read())
                {
                    var updatetasks = new updatetasks();
                    updatetasks.label = reader["taskName"].ToString();
                    updatetasks.value = reader["taskID"].ToString();
                    yield return updatetasks;
                }
            }
        }
    }
}

如何修改我的C＃代码以在JSON对象的开头添加这两个项目？

Answer 1

通过返回您想要的对象。

将您的ajax调用更改为此方法并将其返回。

public object MyCall(string dvprid)
{
    return new
    {
        options = new
        {
            logan_dvprTasks = GetAllItems(dvprid)
        };
    };
}

请注意.（点）对C＃标识符无效，因此我只是logan_dvprTasks.taskID致电logan_dvprTasks。

如果您的意思是taskID是logan_dvprTasks的属性，那么生成的JSON就是

{"options":{"logan_dvprTasks":{"taskID":[...]}}}

修改从C＃AJAX调用返回的JSON数据

1 个答案: